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3 years ago

How to do question 22?

Mathematics

1 answer:

Aleks04 [339]3 years ago

6 0

Answer:

A = 20sinθ(6 + 5 cosθ) cm²

Step-by-step explanation:

Drop perpendiculars DE and CF to AB.

Then, we have congruent triangles ADE and BCF, plus the rectangle CDEF.

The formula for the area of the trapezium is

A = ½(a + b)h

DE = 10sinθ

AE = 10cosθ

BF = 10cosθ

EF = CD = 12 cm

AB = AE + EF + BF = 10cosθ + 12 + 10 cosθ = 12 + 20cosθ

A = ½(a + b)h

= ½(12 +12 + 20 cosθ) × 10 sinθ

=(24 + 20 cosθ) × 5 sinθ

= 4(6 + 5cosθ) × 5sinθ

= 20sinθ(6 + 5 cosθ) cm²

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3 years ago

Solve the system of equations. y = x − 5 and y = x2 − 5x + 3 A. (-4,-9) and (-2,-7) B. (4,-9) and (2,-7) C. (4,-3) and (2,-1) D.

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3 years ago

Read 2 more answers

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Answer:

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