All categories

4 years ago

HELP!!PLZ!!ASAP!!!!!!!

Chemistry

2 answers:

katovenus [111]4 years ago

8 0

A is the answer.i hope lol

professor190 [17]4 years ago

3 0

The answer is A an electrical resistor

You might be interested in

If you don't use your muscles, they will get weaker and smaller, which is called:

Verizon [17]

Answer:

The correct answer would be atrophy.

Explanation:

I hope this helps you:)

4 0

3 years ago

Which of these is the scientific name for the organism? Question 1 options: puma concolor

allochka39001 [22]

Answer:

All of the above

Explanation:

Panthers, pumas, and mountain lions are all the same animal. Just different names. So, all of these would be correct.

3 0

3 years ago

Concentrated hydrochloric acid is an aqueous solution that is 34.70 % HCl. The density of the solution is 1.19 g/mL. What mass o

mixas84 [53]

The mass of HCl that is contained in the solution is 147 g HCl

Why?

To find the mass of HCl we have to apply what is called a conversion factor. In a conversion factor we put the units we don't want at the bottom, and the ones we want at the top.

For this question, we want to go from liters of solution to mass of HCl, and the conversion factor is laid out as follows:

$0.356Lsolution*\frac{1000mL}{1L}*\frac{1.19 g solution}{1 mL solution}*\frac{34.70 g HCl}{100 g solution}=147 g HCl$

Have a nice day!

#LearnwithBrainly

3 0

4 years ago

7) For the reaction 9A (g) + B (g)  5C(g) + 1/6 D (g), it takes 4 and a half minutes for the concentration of C to increase to

viva [34]

Answer: The correct option is, (C) 0.53

Explanation:

The given chemical reaction is:

$9A(g)+B(g)\rightarrow 5C(g)+\frac{1}{6}D(g)$

The rate of the reaction for disappearance of A and formation of C is given as:

$\text{Rate of disappearance of }A=-\frac{1}{9}\times \frac{\Delta [A]}{\Delta t}$

Or,

$\text{Rate of formation of }C=+\frac{1}{5}\times \frac{\Delta [C]}{\Delta t}$

where,

$\Delta C$ = change in concentration of C = 1.33 M

$\Delta t$ = change in time = 4.5 min

Putting values in above equation, we get:

$\frac{1}{9}\times \frac{\Delta [A]}{\Delta t}=\frac{1}{5}\times \frac{\Delta [C]}{\Delta t}$

$\frac{\Delta [A]}{\Delta t}=\frac{9}{5}\times \frac{\Delta [C]}{\Delta t}$

$\frac{\Delta [A]}{\Delta t}=\frac{9}{5}\times \frac{1.33M}{4.5min}$

$\frac{\Delta [A]}{\Delta t}=0.53M/min$

Thus, the decrease in A during this time interval is, 0.53

5 0

3 years ago

What is the formula for<br>a. mercury (ll) nitride<br>b. Cobalt (ll) bromide

Over [174]

Answer:

a Hg(NO3)2

b CoBr2,CoBr2·6H2O,CoBr2·2H2O

Explanation:

6 0

3 years ago