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3 years ago

Solve the simultaneous equations 4x-2y=8 AND x-3y= -3 SHOW ALL WORKINGS PLS

1 answer:

6 0

4x-2y=8
x-3y=-3
Multiply equation 2 by 4;
4x-2y=8
4x-12y=-12
Subtracting equation II from equation I;
10y=20
y=2
Replacing the value of y in equation;
4x-2y=8
4x-2(2)=8
4x-4=8
4x=12
<span>x=3</span>

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The volume of a 10 ounce box of cheerios is 258.75in3. the length of the box is 4 inches less than the height and the width is 3

Marina86 [1]

Answer:

Height of the box = 11.5 in

Step-by-step explanation:

Let h be the height of the box.

Assuming the volume of the Box is $258.75\ in^3$ .

Given:

Length = Height - 4 = h - 4

Width = 3 in

We need to find the height of the box.

Solution:

We know that the volume of the box.

$Volume = Length\times height\times width$

Substitute all given value in above formula.

$258.75 = (h-4)\times h\times 3$

Rewrite the equation as:

$258.75 = 3h(h-4)$

$258.75 = 3h^2-12h$

$3h^2-12h-258.75=0$

whole equation divided by 3.

$h^2-4h-86.25=0$

Use quadratic formula with $a = 1, b = -4,c=-86.25$

$h=\frac{-b\pm \sqrt{(b)^{2}-4ac}}{2a}$

Put these a, b and c value in above equation.

$h=\frac{-(-4)\pm \sqrt{(-4)^{2}-4(1)(-86.25)}}{2(1)}$

$h=\frac{4\pm \sqrt{16+345}}{2}$

$h=\frac{4\pm \sqrt{361}}{2}$

$h=\frac{4\pm 19}{2}$

For positive sign

$h=\frac{23}{2}$

h = 11.5 in

For negative sign

$h=\frac{-15}{2}$

h = -7.5

We take positive value of h.

Therefore, the height of the box h = 11.5 in

4 0

3 years ago

Find the interior angle sum for the following polygon

wolverine [178]

Answer:

1620°

Step-by-step explanation:

The figure is an 11-sided polygon and is called hendecagon

The interior angle sum:

180( n-2) n=11

=180(11-2)

=180(9)

=1620°

I hope this help you

5 0

3 years ago

The perimeter of square F is 23 meter less than the perimeter of square G.

Zigmanuir [339]

Answer: b

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7 0

3 years ago

Solve the following inequality. 21<_-3(x - 4) < 30 A. 28<_x < 37 B. -3 <_ x < 6 C. -6 < x <_ -3 D. -10 &

Aloiza [94]

Answer:

Option C $-6$

Step-by-step explanation:

we have

$21\leq -3(x-4)$

The compound inequality can be divided into two inequality

$21\leq -3(x-4)$ -----> inequality A

$-3(x-4)$ ----> inequality B

Solve inequality A

$21\leq -3x+12$

$9\leq -3x$

Divide by -3 both sides

when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$-3\geq x$

Rewrite

$x\leq -3$

The solution of the inequality A is the interval (-∞,-3]

Solve the inequality B

$-3x+12$

$-3x$

Divide by -3 both sides

when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$x>-6$

The solution of the inequality B is the interval [-6,∞)

The solution of the compound inequality is

[-6,∞) ∩ (-∞,-3]=(-6,-3]

$-6$

3 0

3 years ago

(17x + 21)<br> 123<br> need the answer asap

Greeley [361]

What are we trying to solve?

7 0

3 years ago

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