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Volgvan
2 years ago
8

How do you plot y=3x+2

Mathematics
1 answer:
Ghella [55]2 years ago
3 0

Answer:

Dbdsbedbnsndjjd

Step-by-step explanation:

Bud snnskns

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$15.60 to $11.70<br> ANSWER RIGHT<br> I WILL GIVE BRAINLIEST
galben [10]

Answer:

25% .

Step-by-step explanation:

6 0
3 years ago
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Find the domain and range of the function graphed in the picture.
algol [13]

The domain is the set of allowed x inputs, or x coordinates of a function. In this case, any point on the curve has an x coordinate that is 4 or smaller.

Therefore, the domain is the set of numbers x such that x \le 4

To write this in interval notation, we would write (-\infty, 4] This interval starts at negative infinity and stops at 4. We exclude infinity with the curved parenthesis and include 4 with the square bracket.

-----------------------------------------------------------------------

The range is the set of possible y outputs. Every point on this curve has a y coordinate that is either 0 or it is larger than 0.

The range is the set of y values such that y \ge 0

In interval notation, it would be written as [0, \infty) This time we start at 0 (including this endpoint) and "stop" at infinity

note: we always use curved parenthesis at positive or negative infinity because we cannot reach either infinity

7 0
3 years ago
Erin writes the set of ordered pairs below. The set represents a function.
tino4ka555 [31]
Point A shows that she is incorrect.
With functions, you can perform the "straight line test through each point. If the line goes through both points, you know it's not a function.
If we plotted point A, it'd fail the straight line test because the given point (-6, 7) already has -6 as an x value.
Hope this helps!
7 0
3 years ago
What is 20% of 120 ??? HELP ME
maksim [4K]

Answer:

24

Step-by-step explanation:

3 0
2 years ago
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Perfect squares. Solve each equation. Check the solutions. g^2+2/3g+1/9=0
Yakvenalex [24]
G^2+2=0,
g^2=-2
g= sqrt-2, not possible.
3g+1=0
3g=-1
g=-1/3
9 cannot be equal to zero for the last one.
6 0
3 years ago
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