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Alja [10]
3 years ago
5

Andy, who loves to cook, makes apple cobbler for his family. The recipe (serves 6) calls for 434 pounds of apples, 514 cups of f

lour, 16 cup of margarine, 278 cups of sugar, and 2 teaspoons of cinnamon. Since guests are coming, Andy wants to make a cobbler that will serve 15 (or increase the recipe 212 times). How much of each ingredient should Andy use?
Mathematics
1 answer:
Tamiku [17]3 years ago
5 0

This question was not written properly

Complete question;

Andy, who loves to cook, makes apple cobbler for his family. The recipe (serves 6) calls for 4 3/4 pounds of apples, 5 1/4 cups of flour, 1/6 cup of margarine, 2 7/8 cups of sugar, and 2 teaspoons of cinnamon. Since guests are coming, Andy wants to make a cobbler that will serve 15 (or increase the recipe 2 1/2 times). How much of each ingredient should Andy use?

Answer:

To serve 15, number of ingredients Andy should use =

Apples = 11 7/8 pounds

Flour = 13 1/8 cups

Margarine = 5/12 cups

Sugar = 7 3/16 cups

Cinnamon = 5 teaspoons.

Step-by-step explanation:

The recipe (serves 6) calls for 4 3/4 pounds of apples, 5 1/4 cups of flour, 1/6 cup of margarine, 2 7/8 cups of sugar, and 2 teaspoons of cinnamon. Since guests are coming, Andy wants to make a cobbler that will serve 15 (or increase the recipe 2 1/2 times). How much of each ingredient should Andy use?

For Apples

Serving for 6 = 4 3/4 pounds of apples

Serving for 15 =

= 15 × 4 3/4 pounds/6

= 11 7/8 pounds of apples

For flour

6 servings = 5 1/4 cups of flour,

15 servings =

15 × 5 1/4 cups/6

= 13 1/8 cups of flour

For Margarine

6 servings = 1/6 cups of margarine

15 servings =

= 15 × 1/6 cups/6

= 5/12 cups of margarine

For Sugar

6 servings = 2 7/8 cups of sugar

15 servings =

15 × 2 7/8 cups/6

= 7 3/16 cups of sugar

For Cinnamon

6 servings = 2 teaspoons of cinnamon

15 servings =

15 × 2/6

= 5 teaspoons

Therefore, to serve 15, number of ingredients Andy should use =

Apples = 11 7/8 pounds

Flour = 13 1/8 cups

Margarine = 5/12 cups

Sugar = 7 3/16 cups

Cinnamon = 5 teaspoons.

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Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

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\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

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Answer:

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Step-by-step explanation:

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