Answer:
Given,
Mass, m = 2kg
Height or distance, s = 20m
Initial velocity, u = 0m/s
Acceleration due to gravity, g = 10m/s (It is 9.8m/s but can be assumed 10m/s for simplifying calculations)
(Because the object is is just dropped)
Final velocity, v = ?
Solution
v^2 = u^2 + 2as (u^2 means u raised to power 2)
=> v^2 = 0^2 + 2*10*20
=> v^2 = 400
=> v = 20
Thus the velocity just before the body strikes the ground will be 20m/s.
Answer:90N
Explanation:
Mass=30kg
Centripetal acceleration=3m/s^2
centripetal force=mass x centripetal acceleration
Centripetal force=30 x 3
Centripetal force =90
Centripetal force =90N
Answer:
other part will move with momentum 0.5 kg m/s towards west
Explanation:
As we know that the during the explosion event the time interval is very small and there is no impulsive force on the firecracker during this time
so here we can say that the momentum will remains conserved during the this event
now if the initial momentum of the firecracker is zero
then the final momentum must be zero
so here we can say

towards east
now from above equation

so the other part will move with momentum 0.5 kg m/s towards west