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Vinvika [58]
2 years ago
6

How are the current and resistance related when the voltage if a circuit is constant

Physics
1 answer:
sveta [45]2 years ago
3 0

Answer:

They are inversely proportional

Explanation:

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The acceleration of gravity on Earth is approximately 10 m/s2 (more precisely, 9.8 m/s2). If you drop a rock from a tall buildin
mars1129 [50]

Answer:

30 m/s

Explanation:

Velocity is v_{final}=v_{initial}+at since we know that the initial velocity is 0, and the acceleration is 9.8 \frac{m}{s^2} \approx 10 \frac{m}{s^2} then we also know that time is 3 seconds it follows that: v_{final}=v_{initial}+at=0+10\frac{m}{s^2}*3s=30\frac{m}{s}

8 0
3 years ago
Can someone help me pls!!
Katen [24]

Answer:

Decelerating

Explanation:

One arrow is moving it forward but the other arrow is using more force to move it backwards causing it to have a reduction in speed.

5 0
3 years ago
A 25.0kg girl pushes a 50.0kg boy so that he accelerates at 4.00m/s2. What is the force of the boy on the girl? A. 200N B. 100N
Fynjy0 [20]

Answer:

a

Explanation:

so the answer is 200N

and I hope it is correct

8 0
3 years ago
A race-car drives around a circular track of radius RRR. The race-car speeds around its first lap at linear speed v_iv i ​ v, st
OLEGan [10]

Answer:

The magnitude of the centripetal acceleration increases by 16 times when the linear speed increases by 4 times.

Explanation:

The initial centripetal acceleration, a of the race-car around the circular track of radius , R with a linear speed v is a = v²/R.

When the linear speed of the race-car increases to v' = 4v, the centripetal acceleration a' becomes a' = v'²/R = (4v)²/R = 16v²/R.

So the centripetal acceleration, a' = 16v²/R.

To know how much the magnitude of the car's centripetal acceleration changes, we take the ratio a'/a = 16v²/R ÷ v²/R = 16

a'/a = 16

a' = 16a.

So the magnitude of the centripetal acceleration increases by 16 times when the linear speed increases by 4 times.

8 0
3 years ago
The national high magnetic field laboratory holds the world record for creating the strongest magnetic field. for brief periods
max2010maxim [7]

Newton’s 2nd law states that Force is equal to the product of mass (m) and acceleration (a):

F = m a                                  ---> 1

While in magnetic forces, force can also be expressed as:

F = q v B                               ---> 2

where,

q = total charge

v = velocity = 45 cm / s = 0.45 m / s

B = the magnetic field = 85 T

First we solve for the total charge, q:

q = 3.8 × 10^-23 g (1 mol / 23 g) (6.022 × 10^23 electrons / mol) (1.602 × 10^-19 C / electron)

q = 1.594 × 10^-19 C

 

We equate equations 1 and 2 then solve for acceleration a:

m a = q v B

a = q v B / m

a = [1.594 × 10^-19 C * 0.45 m / s * 85 T] / 3.8 × 10-26 kg

a = 160,437,862.2 m/s^2

 

Therefore the maximum acceleration of Na ions is about 160 × 10^6 m/s^2.

5 0
3 years ago
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