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snow_lady [41]
2 years ago
5

A computer printer has a width of 18in. What is it’s width in meters

Physics
2 answers:
Savatey [412]2 years ago
6 0

Answer:

0.4572 m

Explanation:

To convert inch to metre, divide the value by 39.37.

=》1 inch = 0.0254 metre

So,

18/39.37 = 0.4572 m

Hope it helps ⚜

zimovet [89]2 years ago
3 0

Answer: 0.4572 meters :)

Explanation:

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A force of 30 N is applied tangentially to the rim of a solid disk of radius 0.10 m. The disk rotates about an axis through its
den301095 [7]

Answer:

m = 4.0 Kg

Explanation:

  • Using an analogy with the Newton's 2nd law for point masses, for rigid bodies, the external net torque on a rigid body, is equal to its rotational inertia (I), times the angular acceleration (α) of the body, as follows:

       \tau_{ext} = I* \alpha (1)

  • Since the magnitude of the torque is the product of the value of the force times the perpendicular distance between the line of action of  the force and the axis of rotation, and the force is tangential to the rim of the disk, we can write the following expression:

       \tau = F*r*sin 90 = F*r (2)    

  • For a solid disk, the rotational inertia regarding an axis through its center, and perpendicular to its face is as follows:

      I = \frac{m*r^{2}}{2}  (3)

  • Replacing (3) in (1), and (2) in the left side of (1) also, we can solve for m, as follows:

       m = \frac{2*30.0N}{0.1m*150(1/s2)} = 4.0 Kg (4)

  • So, the mass of the disk is 4.0 Kg.
7 0
3 years ago
A parallel-plate capacitor has plates with an area of 451 cm2 and an air-filled gap between the plates that is 2.51 mm thick. Th
Nostrana [21]

To solve this problem we will apply the concepts related to Energy defined in the capacitors, as well as the capacitance and load. From these three definitions we will build the solution to the problem by defending the energy with the initial conditions, the energy under new conditions and finally the change in the work done to move from one point to the other.

Energy in a capacitor can be defined as

E = \frac{1}{2}CV^2 = \frac{1}{2}\frac{Q^2}{C}

Here,

V = Potential difference across the capacitor plates

Q = Charge stored on the capacitor plates

At the same time capacitance can be defined as,

C = \epsilon_0 (\frac{A}{d})

Here,

\epsilon_0 =  Vacuum permittivity constant

A = Area

d = Distance

Replacing with our values we have that,

C = (8.85*10^{-12})(\frac{0.0451}{2.51*10^{-3}})

C = 1.5901*10^{-10}F

PART A) Energy stored in the capacitor is

E = \frac{1}{2} CV^2

E = \frac{1}{2} (1.5901*10^{-10})(575)^2

E = 2.628*10^{-5}J

PART B) We know first that everything that the load can be defined as the product between voltage and capacitance, therefore

Q = CV

Q = (1.59*10^{-10})(575)

Q = 9.1425*10^{-8}C

Now if d = 10.04*10^{-3}m we have that the capacitance is

C = \epsilon_0 (\frac{A}{d})

C = (8.85*10^{-12})(\frac{0.0451}{10.04*10^{-3}})

C = 3.9754*10^{-11}F

Then the energy stored is

E = \frac{1}{2} \frac{Q^2}{C}

E = \frac{1}{2} (\frac{(9.1425*10^{-8})^2}{3.9754*10^{-11}})

E = 1.051*10^{-4} J

PART C) The amount of work or energy required to carry out this process is the difference between the energies obtained, therefore

W = 1.051*10^{-4} J -2.628*10^{-5}J

W = 7.882*10^{-5} J

6 0
3 years ago
Lillie is running. She increases her initial speed of 30 km/h to 40 km/h so she can win the race. If she takes 0.05 hours to com
Rudiy27

Answer:

200 km/h²

Explanation:

<em>Use the formula:</em>

acceleration = (final velocity - initial velocity) ÷ time taken

final velocity = 40 km/h

initial velocity = 30 km/h

time taken = 0.05 hours

<em>Substitute (plug in) the values into the equation:</em>

acceleration = (40 - 30) ÷ 0.05

acceleration = 10 ÷ 0.05

acceleration = 200 km/h²

7 0
3 years ago
What is the approximate size of Earth’s magnetic field? Where are Earth’s magnetic poles? Where is the magnet that causes Earth’
nataly862011 [7]
Earths poles are on opposite sides of the earth
7 0
3 years ago
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Just show a picture so I can help ur information is misleading...
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