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kondaur [170]
3 years ago
15

Compared to the inertia of a 1-kilogram mass, the inertia of a 4-kilogram mass is​

Physics
1 answer:
Mumz [18]3 years ago
5 0

Explanation:

The inertia of a 4 kg mass is four times as great as a 1 kg mass.

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What is net force
IgorLugansk [536]
The answer is letter A
3 0
3 years ago
Diya visited a tailor shop and bought home three cuttings of fabric A,B and C to study their properties. Diya tried burning the
andreev551 [17]

Answer:

Rayon

Wool

Silk Yarn

Explanation:

Rayon

This is Fabric A. Rayon basically burns very quickly even quicker than fabrics like cotton and linen. Its ash is gray in color. The rayon fabric smells of burning paper when it is burnt.

Wool:

This is Fabric B. Wool is basically hard to ignite. It burns slowly. Its ash is dark in color. The wool fabric smells of burning hair when it is burnt.

Silk Yarn:

This is Fabric C. The silk yarn shrinks from the flame when it is burned. It has a grayish black ash. The silk yarn fabric smells burnt meat of  when it is burnt.

3 0
3 years ago
A virtual image is formed 17.0 cm from a concave mirror having a radius of curvature of 39.0 cm. (a) Find the position of the ob
Wittaler [7]

Explanation:

Image distance, v = -17 cm (-ve for virtual image)

Radius of curvature of concave mirror, R = 39 cm

Focal length, f = -19.5 cm (-ve for a concave mirror)

(a) Using mirror's formula as :

\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}

\dfrac{1}{u}=\dfrac{1}{f}-\dfrac{1}{v}

\dfrac{1}{u}=\dfrac{1}{-19.5}-\dfrac{1}{(-17)}  

u = 132.6 cm    

So, the object is placed 132.6 cm in front of the mirror.

(b) Magnification of the  mirror, m=\dfrac{-v}{u}

m=\dfrac{-17}{132.6}

m = -0.128

Hence, this is the required solution.

7 0
3 years ago
A substance has a volume of 10.0 cm3 and a mass of 89 grams. What is its density?
vovikov84 [41]
Density = mass / volume

D = 89 / 10.0

D = 8.9 g/cm³

hope this helps!
8 0
3 years ago
physics Test 2 In a double slit experiment, if the separation between the two slits is 0.050 mm and the distance from the slits
Ipatiy [6.2K]

Answer:0.015 m

Explanation:

Given

distance between two slits(d)=0.050 mm

Distance between slit and screen=2.5 m

Wavelength(\lambda )=600 nm

and distance between First order and second order=\frac{D\lambda }{2d}

=\frac{2.5\times 600\times 10^{-9}}{2\times 5\times 10^{-5}}

=15\times 10^{-3}

=0.015 m

8 0
3 years ago
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