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nignag [31]
3 years ago
12

I need help I forgot how to do this helppppppppppp!!!!!!!!!!!

Mathematics
1 answer:
jekas [21]3 years ago
6 0

Answer:

it's a trapezoid

Step-by-step explanation:

((major base + minor base) x height) / 2

((7+5)x8) / 2 = 52

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If the endpoints of the diameter of a circle are (6, 3) and (2, 1), what is the standard form equation of the circle?
Anastasy [175]
If the endpoints of a diameter are (6,3) and (2,1) the midpoint is the center of the circle so:

(x,y)=((6+2)/2, (3+1)/2)=(4,2)

Now we need to find the radius....the diameter is:

d^2=(6-2)^2+(3-1)^2

d^2=16+4

d^2=20  since d=2r, r=d/2, and r^2=d^2/4 so

r^2=5

The standard form of the circle is (x-h)^2+(y-k)^2=r^2 and we know:
 
(h,k)=(4,2) from earlier so:

(x-4)^2+(y-2)^2=5
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3 years ago
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3 years ago
What is the equation of the line whose Y intercept of three and So what is the equation of the line whose Y-intercept is 3 and s
viva [34]

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3 years ago
Preform the indicated operation and express the answer in simplest radical form
tigry1 [53]

hello

the question here is

3\sqrt[]{7}(14-4\sqrt[]{56})

step 1

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\begin{gathered} 3\sqrt[]{7}(14-4\sqrt[]{56}) \\ (3\sqrt[]{7}\times14)-(3\sqrt[]{7}\times4\sqrt[]{56}) \\ (14\times3\sqrt[]{7})-3\sqrt[]{7}\times4\sqrt[]{4\times14} \\ (42\sqrt[]{7})-3\sqrt[]{7}\times8\sqrt[]{14} \\ (42\sqrt[]{7})-\lbrack(3\times8)\sqrt[]{7\times14} \\ 42\sqrt[]{7}-24\sqrt[]{98} \end{gathered}\begin{gathered} 42\sqrt[]{7}-24\sqrt[]{49\times2} \\ 42\sqrt[]{7}-24\times7\sqrt[]{2} \\ 42\sqrt[]{7}-168\sqrt[]{2} \end{gathered}

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1 year ago
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