When lines coincide how many solutions does each system have?
2 answers:
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Answer:
(4,0)
Step-by-step explanation:
we have
----> inequality A
----> inequality B
we know that
If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
Verify each ordered pair
case 1) (4,0)
<em>Inequality A</em>
----> is true
<em>Inequality B</em>
----> is true
so
the ordered pair makes both inequalities true
case 2) (1,2)
<em>Inequality A</em>
----> is not true
so
the ordered pair not makes both inequalities true
case 3) (0,4)
<em>Inequality A</em>
----> is not true
so
the ordered pair not makes both inequalities true
case 4) (2,1)
<em>Inequality A</em>
----> is true
<em>Inequality B</em>
----> is not true
so
the ordered pair not makes both inequalities true
Answer:
a¹⁰
Step-by-step explanation:
So here we have (a⁵)², meaning we need to multiply the exponents to get a¹⁰