My guess would be guess A
I don’t see the picture to help you
Answer:
see explanation
Step-by-step explanation:
(a)
Given
2k - 6k² + 4k³ ← factor out 2k from each term
= 2k(1 - 3k + 2k²)
To factor the quadratic
Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)
The factors are - 1 and - 2
Use these factors to split the k- term
1 - k - 2k + 2k² ( factor the first/second and third/fourth terms )
1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term
= (1 - k)(1 - 2k)
1 - 3k + 2k² = (1 - k)(1 - 2k) and
2k - 6k² + 4k³ = 2k(1 - k)(1 - 2k)
(b)
Given
2ax - 4ay + 3bx - 6by ( factor the first/second and third/fourth terms )
= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term
= (x - 2y)(2a + 3b)
Answer:
41
Step-by-step explanation:
an = a1 + (n-1)d
a_n = the nᵗʰ term in the sequence = 10
a_1 = the first term in the sequence = 5
d = the common difference between terms = 4
a10 = 5 + (10-1)4
a10 = 5 + (9)4
a10 = 5 + 36
a10 = 41
Answer:
c i think sorry if i get it wrong
Step-by-step explanation:
