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elena-s [515]
3 years ago
11

The output of a function is 5 more than 2 times the input. Find the input when the output is 17.

Mathematics
1 answer:
Tanya [424]3 years ago
7 0

Answer:

<em>The input when the output is 17 is x=6.</em>

Step-by-step explanation:

<u>Functions</u>

Assume the input is called x and the output is the function f(x). Two times the input is 2x. 5 more than that is 2x+5.

Knowing the output of the function is 5 more than 2 times the input, we can write the function as:

f(x)=2x+5

Now find the input x when the output is 17:

17=2x+5

Swap sides of the equation:

2x+5=17

Subtract 5:

2x=17-5=12

Divide by 2:

x=12/6=6

The input when the output is 17 is x=6.

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How to calculate 99 : 5​
Goryan [66]

Answer:

19.8

Step-by-step explanation:

99/5= 19.8

5 0
3 years ago
What is the quantity proportional to 18/6
mario62 [17]

Answer:

18/6=3

Step-by-step explanation:

18/6÷3=6/2

6/2=3

7 0
3 years ago
3. A quadratic polynomial whose<br>product and the sum of<br>zéroes are -12 and 1​
muminat

Answer:

the equation is : x²-x-12

Step-by-step explanation:

the quadratic equation is in the form of : y=ax²+bx+c

the product of the zeros is -12 and the sum is 1

b  = - 1

c=-12 (product)

y=x²-x-12

check : factorize first (x+3)(x-4)=0

either x+3=0 then x=-3

or x-4=0 then x=4

-3*4=-12

-3+4=1

the equation is : x²-x-12

3 0
3 years ago
Please answer I’ll rate brainlyest
12345 [234]

Answer:

5P3*6C4=60*15=900

Step-by-step explanation:

5P3 refers to the permutations of 5 items taken 3 at a time. To evaluate this, we use factorials as follows;

5P3=\frac{5!}{(5-3)!}

The factorial of an integer n is evaluated as;

n!=n*(n-1)*(n-2)*(n-3).......3*2*1

Using this concept, the above expression can now be simplified as follows;

5P3=\frac{5!}{2!}=\frac{5*4*3*2!}{2!}=5*4*3=60

Therefore, the permutations of 5 items taken 3 at a time is 60.

The next expression, 6C4 refers to the combinations of 6 items taken 4 at a time. The simplification utilizes similar concepts of permutations since we shall be involving factorials;

6C4=\frac{6!}{4!(6-4)!}=\frac{6!}{4!*2!}=\frac{6*5*4!}{4!*2*1}=\frac{6*5}{2*1}=15

Therefore, the combinations of 6 items taken 4 at a time is 15.

The final step is to evaluate the product;

5P3*6C4=60*15=900

3 0
3 years ago
Three dogs for each cat <br><br><br><br>a) d=3c<br>b) 3d=c<br>c) d= 3/c <br>d) c=3/d
ivanzaharov [21]
The answer is would have to be b.
7 0
3 years ago
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