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Mrac [35]
3 years ago
14

Make up an equation of the form y = kx +b, the graph of which passes through the following points: A (8, –1) and B (–4, 17)

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0

Answer:

One equation would be y= -1.5x +11

Step-by-step explanation:

Here's a table to show the coordinates

x:             y:

8              -1

-------------------

-4             17

the x coor. 8  goes down by 12 to get to the next x coor. -4.

8-12= -4

the y coor. -1 goes up by 18 to get to the next y coor. 17.

-1+18= 17

therefore 18/-12 is -1.5 which can be your k in y=kx+b.

Check your answer.

-1.5*8= -12 but when you add 11, you get the y coor. -1

Do the same with the other x coor.

-4*-1.5= 6 + 11 =17

11 can be your b in the slope-intercept form equation.

One equation may be y = -1.5x +11

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Answer:

A) 3/4

Step-by-step explanation:

Given: Both circle A and circle B have a central angle measuring 50°.

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We know, area of the circle= \pi r^{2}

lets assume the radius of circle A be "r_1" and radius of circle B be "r_2"

As given, Area of circle A and B´s sector is 36π and 64π repectively.

Now, writing ratio of area of circle A and B, to find the ratio of radius.

⇒\frac{\pi r_1^{2}  }{\pi r_2^{2} }  = \frac{36\pi }{64\pi }

Cancelling out the common factor

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Taking square on both side.

Remember; √a²= a

⇒ (\frac{r_1  }{r_2} ) =\sqrt{ \frac{36 }{64}}

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Answer:

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