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Mrac [35]
3 years ago
14

Make up an equation of the form y = kx +b, the graph of which passes through the following points: A (8, –1) and B (–4, 17)

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0

Answer:

One equation would be y= -1.5x +11

Step-by-step explanation:

Here's a table to show the coordinates

x:             y:

8              -1

-------------------

-4             17

the x coor. 8  goes down by 12 to get to the next x coor. -4.

8-12= -4

the y coor. -1 goes up by 18 to get to the next y coor. 17.

-1+18= 17

therefore 18/-12 is -1.5 which can be your k in y=kx+b.

Check your answer.

-1.5*8= -12 but when you add 11, you get the y coor. -1

Do the same with the other x coor.

-4*-1.5= 6 + 11 =17

11 can be your b in the slope-intercept form equation.

One equation may be y = -1.5x +11

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the length of a tangent from a point a at distance 5 cm from the centre of the circle is 4 cm find the radius of the circle ​
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<u>Step-by-step explanation:</u>

Refer the attached diagram, the circle with centre O. In that given, AB is tangent given as 4 cm and distance of point from the circle, OA = 5 cm

As AB is tangent, OB (radius of circle) is perpendicular to AB (tangent at any point of circle). Therefore the angle of OBA is 90 degree.

Also, triangle OAB is a right angled triangle (refer attached diagram). By using Pythagoras theorem in right angled triangle,

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