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3 years ago

The equation of a circle is given. What is the diameter of the circle? Round to the nearest tenth.

Mathematics

1 answer:

Law Incorporation [45]3 years ago

8 0

Answer:

14.2 is the diameter.

Step-by-step explanation:

The radius squared = 52.

What you have given is the general equation of the circle with a center at (2,-3) and a radius of sqrt(52)

You can break the 52 down.

sqrt(52) = sqrt(4 * 13) = 2 sqrt(13). Notice that 4 is a perfect square.

d = 2*radius.

d = 2(2 sqrt(13) )

d = 4 sqrt(13)

That is the diameter. You want it to the nearest 1/10

d = 14.222 but it is to the nearest 1/10

d = 14.2

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Jesse and her brothers nick and owen are saving money over the summer each week, jesse saves twice as much as owen. Owen saves $

Harrizon [31]

If how much owen saves is x, 2x=y (jessie's amount of saved money) and
x-5=nick's amount of money =z

Since x+y+z=220, we plug 2x in for y and x-5 in for z, getting x+2x+x-5=220. Adding 5 to both sides, we get 4x=225 and by dividing by 4 we get x=225/4=61.25 dollars. 61.25-5=56.25=z=nick's money, and 61.25*2=122.5=jessie's saved money

7 0

4 years ago

50 points and brainly

Andre45 [30]

Answer:

Part A:

c = .86*p

c =1.72 for 2 lbs

Part B:

c =.81p

Step-by-step explanation:

Part A:

Total cost = cost per pound * number of pounds

c = .86*p

Let p = 2

c = .86*2

c =1.72

Part B:

Total cost = cost per pound * number of pounds

c = .(.86-.05)*p

c =.81p

5 0

3 years ago

Add or subtract the polynomials

Mashcka [7]

Answer:

7xy + 6y + 6xy is a polynomial who’s like terms are 7xy and 6xy. Therefore, this polynomial can be simplified by combining like terms as 7xy +6xy +6y = 13xy + y. When combining like terms, we only add or subtract the coefficients of the identical variables.

On the other hand, unlike terms are terms which are not identical in terms of either variables or exponents.

For example, an expression 4x + 9y2, contain unlike terms because variable x and y are different and are not raised to the same power.

5 0

3 years ago

Read 2 more answers

Can the mean value theorum be applied to the function f(x)=1/x^2 on the interval [-2, 1]? Explain.

Temka [501]

Answer:

No, it can not be applied.

Step-by-step explanation:

f(x) = 1/x²

f(x) is a polynomial that is not continuous

As,

f(x) = 1/0 is undefines

Secondly, it is not differentiable (i.e. the derivative does not exists on the interval given)

Derivative of this function

f'(x) = (1)x^-2

= -2x^(-2-1)

= -2x^(-3)

= -2/x³

f'(0) = -2/0 is undefined

Thus, mean value theorem can not be applied.

7 0

4 years ago

Which graph represents viable values for y = 5.5x, where x is the number of cans of tomato paste and y is the total weight of th

Brilliant_brown [7]

Answer:

On a coordinate plane, x-axis is numbered negative 5 to positive 5 in increments of 1, and the y-axis is numbered negative 27.5 to 27.5 in increments of 5.5. Solid circles appear at points (0, 0), (1, 5.5), (2, 11), (3, 16.5), (4, 22), (5, 27.5)

Step-by-step explanation:

The first graph is not correct because you cannot sell or buy, for example 1.1, cans of tomato.

The second graph is correct because x is discrete variable, that is, it only take values like 1, 2, 3, etc.

The third and fourth graphs are not correct because you cannot sell or buy negative cans of tomatoes.

6 0

3 years ago

Read 2 more answers