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Aleksandr [31]
3 years ago
11

The sum of 6 consecutive integers is 393. What is the third number in this sequence?​

Mathematics
1 answer:
Viefleur [7K]3 years ago
8 0

Answer:

Let the six consecutive integers be x , x+1 , x+2 , x+3 , x+4 and x+5 . and third number is 63+2=65 .

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You take the x and change it to the other side to leave y by itself and then divide by 2 = Y=-3-x
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The sum of 20.7 and a number is 50.5. Which equation could you use to solve the problem? What should you do to each side of the
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Answer:

Equation to solve this: 50.5-20.7=a number

Answer: 29.8

Step-by-step explanation:

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It should be $92.00

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I need help with three and four
mart [117]

Answer:

3: a^{2}+2ab+b^{2}

4: 8x^{3} -12x^{2}+6x-1

Step-by-step explanation:

Question 3 can be re-written as:

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which equals:

a^{2}+2ab+b^{2}

Question 4 can be re-written as:

(2x-1)(2x-1)(2x-1)

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Simplifying it:

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4 0
2 years ago
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(5x^2-4X + 7) - (4x + 2)
DanielleElmas [232]
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We add the two 4
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