You want to design amplification and filtering circuitry to record axon action potential (AAP) signal on your Arduino microcontr
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Answer:
The values of i_x,i_y and i_z as 25 mA, -25 mA and 15 mA while that of V_Δ is -25 V
Explanation:
As the complete question is not given the complete question is found online and is attached herewith.
By applying KCL at node 1
Also
Now applying KVL on loop 1 as indicated in the attached figure
Similarly for loop 2
So the system of equations become
Solving these give the values of i_x,i_y and i_z as 25 mA, -25 mA and 15 mA. Also the value of voltage is given as
The values of i_x,i_y and i_z as 25 mA, -25 mA and 15 mA while that of V_Δ is -25 V
Answer:
The phasor technique can't be applied directly in the following cases:
a) 45 sin(2500t – 50°) + 20 cos(1500t +20°)
b) 100 cos(500t +40°) + 50 sin(500t – 120°) – 120 cos(500t + 60°)
c) -100 sin(10,000t +90°) + 40 sin(10, 100t – 80°) + 80 cos(10,000t)
d) 75 cos(8t+40°) + 75 sin(8t+10°) – 75 cos(8t + 160°)
Explanation:
For a) and c), it is not possible to use the phasor technique, due this technique is only possible when the sinusoidal signals to be combined are all of the same frequency.
This is due to the vector representing a signal is showed as a fixed vector in the graph( which magnitude is equal to the amplitude of the sinusoid and his angle is the phase angle with respect to cos (ωt)), which is rotating at an angular speed equal to the angular frequency of the sinusoidal signal that represents, like a radius that shows a point rotating in a circular uniform movement.
This rotating vector represents a sinusoidal signal, in the form of a cosine (as the real part of the complex function ), so it is not possible to combine with functions expressed as a sine, even though both have the same frequency.
If we look at the graphs of cos (ωt) and sin (ωt) we can say that the sin lags the cos in 90º, so we can say the following:
sin (ωt) = cos (ωt-90º)
This means that in order to be able to represent a sine function as a cosine, we need to rotate it 90º in the plane clockwise.
This is the reason why before doing this transformation, it is not possible to use the phasor technique for b) and d).