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skad [1K]
2 years ago
7

Keesha has 10 more quarters than dimes, which, together, total $11.25. How many coins does she have in quarters and dimes?​

Mathematics
1 answer:
Rom4ik [11]2 years ago
6 0

Assume Keesha has d dimes, so she has d + 10 quarters

Total money Keesha has is (d+10)*.25 + d*.1 = 11.25

or 0.35d + 2.5 = 11.25

Solving for d , d = 25

So Keesha has 25 dimes and 35 quarters, total of 60 coins

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The trapezium is down on a centimetre grid find the area of the trapezium​
docker41 [41]

Answer:

21 square cm

Step-by-step explanation:

b_1 = 9 \:cm, \: b_2 = 5 \:cm, \: h = 3\: cm\\Area\:  of\: trapezium\\ = \frac{1}{2} (b_1 +b_2)\times h\\\\ = \frac{1}{2} (9 +5)\times 3\\\\ = \frac{1}{2} \times 14 \times 3\\\\ = 7 \times 3\\\\= 21 \: cm^2

6 0
4 years ago
Suppose Samhara completes 20 homework problems in 1 hour. How many homework problems can she complete in 4 days
marishachu [46]

Answer: 1920

Step-by-step explanation: She/He( I don’t know ) can do 1920 homework problems in 4 days

3 0
3 years ago
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Cynthia is making peanut butter cookies. Her recipe calls for 2 cup of peanut butter to make 1 dozen cookies. Which fraction bes
lisov135 [29]

Answer:

D I think

Step-by-step explanation:

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6 0
3 years ago
(-5,-4) rotated 270° counterclockwise
stepladder [879]

Answer:

(4, - 5 )

Step-by-step explanation:

Under a counterclockwise rotation about the origin of 270°

a point (x, y ) → (- y, x ) , thus

(- 5, - 4 ) → (4, - 5 )

6 0
3 years ago
Solve for z? 2x-4y+4z-6w=4 6w-4x+4y-4z=-12 6w+4x-2y+6z=64 4z+2w+6y-4x=56
lozanna [386]

Answer:

9.22

Step-by-step explanation:

The calculation of z is shown below:-

Given that

2x-4y+4z-6w=4 .... (1)

6w-4x+4y-4z=-12 ..... (2)

6w+4x-2y+6z=64 ...... (3)

4z+2w+6y-4x=56 .... (4)

Here we need to decrease the equations with the help of canceling out a few variables.

Now we need to add equations 1 and 2 that is

(2x - 4x) + (-4y + 4y) + (4z - 4z) + (-6w + 6w) = 4 + 12

Now we solve the above equation

-2x + 0 = 16

-2x = 16

x = -8

Now, equation 2 minus 3

6w - 6w + (-4x - 4x) + 4y + 2y + (-4z - 6z) = 12 - 64

-8x + 6y - 10z = -52

Now we will put the value of x

-8(-8) + 6y - 10z = -52

64 + 6y - 10z = -52

6y - 10z  = -52 - 64

6y - 10z = -116

3y - 5z = -58 ... 5

Equation 3 × 1 and equation 4 × 3

6w + 4x - 2y + 6z = 64 ..... (3)

4z + 2w + 6y - 4x = 56 .... (4)

6w + 4x - 2y + 6z = 64

12z + 6w + 18y - 12x = 168

Now we will subtract both equations that are

16x - 20y - 6z = -104

8x - 10y - 3z = -52

8(-8) - 10y - 3z = -52

-64 - 10y - 3z = -52

-10y - 3z = -52 + 64

-10y - 3z = 12 ....... (6)

equating 5 and 6 and solving that is

3y - 5z = -58 ... 5 × 10

-10y - 3z = 12 ....... 6 × 3

30y - 50z = -580

-30y - 9z = 36

we will add both equation

-50z - 9z = -580 + 36

-59z = -544

z = -544 ÷ -59

After solving z value we will get

= 9.22

7 0
3 years ago
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