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creativ13 [48]
3 years ago
12

Is rolling doubles a simple event or compound event? Explain.

Mathematics
2 answers:
Mrrafil [7]3 years ago
4 0
You have to consider the sample space. In this example the sample space 
is {1,2,3,4,5,6}
A simple event can be defined as a SINGLE outcome : Example getting a 3 OR 5 OR any other number from the sample space.
Now if you roll 1 dice & you want to get an even number (2,4,6) then you have chosen from the sample space 3 outcome & this is a compound event
Equally if you roll 2 dice and want to get "one" and/or "three" this is a compound event since you have chosen 2 outcome from the sample space.
Mind you, if you want 5 And 5 when rolling two dice it's a simple event because you have chosen ONE outcome from the sample space.
Hope this will help you to understand this kind of problem
blagie [28]3 years ago
3 0
You have to consider the sample space. In this example the sample space

is {1,2,3,4,5,6}

A simple event can be defined as a SINGLE outcome: Example getting a 3 OR 5 OR any other number from the sample space.

Now if you roll one dice & you want to get an even number (2,4,6), then you have chosen from the sample space three outcomes & this is a compound event

Equally, if you roll two dice and want to get "one" and "three," this is a compound event since you have chosen two outcomes from the sample space.

Mind you, if you want 5 And 5 when rolling two dice it's a simple event because you have chosen ONE outcome from the sample space.


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Y is directly proportional to x when y=30, x=6
rosijanka [135]

Answer:

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Step-by-step explanation:

Since, y is directly proportional to x when y=30, x=6

\therefore \:  y \:  \alpha \:  \: x \\ \therefore \:  y =  kx ...(1) \\ plug \: y = 30 \: and \: x = 6  \: in \: eq \: (1)\\ 30 = k \times 6 \\ k =  \frac{30}{6}  \\ k = 5 \\ plug \: k = 5 \: in \: (1) \\ y = 5x....(2) \: (required \: equation) \\ plug \: x = 12 \: in \: eq \: (2) \\ y = 5 \times 12 \\  \huge \red{ \boxed{y = 60}}

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Yuliya22 [10]

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Step-by-step explanation:

3 0
3 years ago
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Brainlyst for the best answer thank you!
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