Answer:
Deceleration of the runner is -23.33
Given:
Initial velocity = 3.5
Final velocity = 0
Time = 0.15 s
To find:
Deceleration of runner = ?
Formula used:
According to first equation of motion,
v = u + at
Where, v = final velocity
u = initial velocity
a = deceleration
t = time
Solution:
According to first equation of motion,
v = u + at
Where, v = final velocity
u = initial velocity
a = deceleration
t = time
0 = 3.5 + a (0.15)
-3.5 = 0.15 (a)
a =
a = -23.33
Negative sign shows that it is deceleration.
Thus, deceleration of the runner is -23.33
Answer:
Option C
Explanation:
given,
velocity of airplane = 80 m/s
angle with the horizontal = 15°
speed of the ground= ?
when the plane is taking off the horizontal component of the velocity is v cosθ
so,
ground speed of the airplane is =
=
v = 77.27 m/s
horizontal velocity of the air plane comes out to be 77.27 m/s ≅ 77 m/s
so, the correct option is Option C
Answer:
efferent pathway
Explanation:
efferent pathway - it is the pathway used by signal to get away from the nervous system. After getting signal from the brain, efferent signal direct body to do according to the received signals.
while on the other side, afferent signals related to the signal that sends by the body to the brain. which is opposite to the efferent signals
the purpose of using a chemical equation is to know the reactants and products that occur.
reactants=starting material
products=end result