The work done by the water at the constant pressure is 
.
<h3>Heat required to boil the water</h3>
The heat required to boil the water is calculated as follows;
where;
is the heat of vaporization of water = 22.6 x 10⁵ J/kg- m is mass of water
<h3>Work done by the water</h3>
The work done by the water at the constant pressure is equal to the heat gained by the water.
.
Learn more about first law of thermodynamics here: brainly.com/question/2965070
You really can't tell.
Power = I^2 × R = V^2 / R ( unit in Watt)
For P = I^2 × R
Where we have P directly proportional to R, increase in Power leads to increase in R
So if we have 100 will have higher resistance
For P = V^2/R
Power is inversely proportional to resistance.
So increase in Power leads to decrease in resistance.
60 watt will have a higher resistance.
Compression is the best answer. Think about pressing on the toy bus enough to bend the table but not break it
Answer:
False.
Separation between channel is required when frequency division multiplexing (FDM) is used to aggregate several modulated channels together.
Explanation:
In Frequency Division Multiplexing (FDM), the total bandwidth is divided to a set of frequency bands that do not overlap. Each of these bands is a carrier of a different signal that is generated and modulated by one of the sending devices.
The frequency bands are separated from one another by strips of unused frequencies called the guard bands, to prevent overlapping of signals.
The modulated signals are combined together using a multiplexer (MUX) in the sending end. The combined signal is transmitted over the communication channel, thus allowing multiple independent data streams to be transmitted simultaneously. At the receiving end, the individual signals are extracted from the combined signal by the process of demultiplexing (DEMUX).
Answer:
- Fx = -9.15 N
- Fy = 1.72 N
- F∠γ ≈ 9.31∠-10.6°
Explanation:
You apparently want the sum of forces ...
F = 8.80∠-56° +7.00∠52.8°
Your angle reference is a bit unconventional, so we'll compute the components of the forces as ...
f∠α = (-f·cos(α), -f·sin(α))
This way, the 2nd quadrant angle that has a negative angle measure will have a positive y component.
= -8.80(cos(-56°), sin(-56°)) -7.00(cos(52.8°), sin(52.8°))
≈ (-4.92090, 7.29553) +(-4.23219, -5.57571)
≈ (-9.15309, 1.71982)
The resultant component forces are ...
Then the magnitude and direction of the resultant are
F∠γ = (√(9.15309² +1.71982²))∠arctan(-1.71982/9.15309)
F∠γ ≈ 9.31∠-10.6°
