Here are the answers to the question. Make sure to give a valid reason, please.
A. the sum of the protons and neutrons in one atom of the element.
B. a ratio based on the mass of a carbon-12 atom.
C. a weighted average of the masses of an element's isotopes.
D. twice the number of protons in one atom of the element.
Answer:
The fraction of the protons would have no electrons 
Explanation:
We are given that
Amoeba has total number of protons=
Net charge, Q=0.300pC
Electrons are fewer than protons=
We have to find the fraction of protons would have no electrons.
The fraction of the protons would have no electrons
=
The fraction of the protons would have no electrons
=

Hence, the fraction of the protons would have no electrons 
1.25 is the answer to tht if im right but could be wrong
B.Electromagnetic
explanation:
Answer:
1.7 BTU
Explanation:
q = mCΔT
q = (25 g) (0.9 J/g/°C) (100°C − 20°C)
q = 1800 J
q = 1800 J × (1 BTU / 1055 J)
q = 1.7 BTU