Answer:
0.333 m
Explanation:
Molality (m) is moles of solute over kilograms of solvent.
Convert grams of the solute (aluminum acetate) to moles.
(29.4 g)/(204.11 g/mol) = 0.144 mol
Convert grams of the solvent (water) to kilograms.
433 g = 0.433 kg
Divide the solute by the solvent.
(0.144 mol)/(0.433 kg) = 0.333 m
The molality of the solution is 0.333 m.
Answer:
Mass = 2.12 g
Explanation:
Given data:
Volume of KMnO₄ = 255 mL (255/1000 = 0.255 L)
Molarity = 0.0525 M
Mass in gram = ?
Solution:
First of all we will calculate the number of moles.
<em>Molarity = number of moles of solute / volume in litter</em>
0.0525 M = number of moles of solute / 0.255 L
Number of moles of solute = 0.0525 M ×0.255 L
Number of moles of solute = 0.0134 mol
Mass in gram:
<em>Number of moles = mass/ molar mass</em>
Mass = moles × molar mass
Mass = 0.0134 mol × 158.04 g/mol
Mass = 2.12 g
BaCO3=BaO+CO2
IS THE EQUATION REPLACE = WITH AN ARROW.
I think the answer is Fe. Hope it help!
I believe the answer is carbon atoms
