Explanation:
The pressure exerted by vapors or gas on the surface of a liquid is known as vapor pressure.
This means that weaker is the intermolecular forces present in a substance more easily it can form vapors. As a result, it will have high vapor pressure.
As substance B has high vapor pressure which means that it has weak intermolecular forces.
Also, stronger is the intermolecular forces present in a substance more will be its boiling point. Hence, more energy or temperature is required to break the bonds. Hence, substance A has higher boiling point and high heat of vaporization.
When surrounding pressure is less than or equal to its vapor pressure then substance B boils into the gas phase. Hence, substance B will be a gas at 300 mm Hg.
Therefore, we can conclude that characteristics of the two substances will be as follows.
(a) Substance B - has weaker intermoclcular
(b) Substance A - has a higher boiling point
(c) Substance B - is a gas at 300 mm Hg
(d) Substance A - has a higher heat of vaporization
First you would multiply 5,3, and 2 to get a volume of 30. Density is mass over volume so you would then divide 129 by 30. You would get 4.3. The answer would be 4.3 g/cm^3
Answer:
Benzene: 37.5 Torr
Methylbenzene: 12.5 Torr
Explanation:
By Raoult's Law, each substance in a gas mixture contributes to the total pressure of the mixture proportionally to their respective mole fraction. So,
Ppartial = x*P°
Where x is the mole fraction (0.5 for each one because it's equimolar), and P° is the vapor pressure.
Benzene: Ppartial = 0.5 * 75 = 37.5 Torr
Methylbenzene: Ppartial = 0.5 * 25 = 12.5 Torr
Answer:
(a) Decomposition: A substance breaks down to smaller species. [e.g. CaCO3(s) → CaO(s) + CO2(g) Decomposition of limestone to calcium oxide (quicklime) and carbon dioxide on heating.]
Answer:
XCl2(aq) + 2 AgNO3(aq) = 2 AgCl(s) + X(NO3)2(aq)
