Answer: ![\sqrt[6]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B2%7D)
Step-by-step explanation:
You know that the expression is ![\frac{\sqrt{2}}{\sqrt[3]{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D)
By definition we know that:
![\sqrt[n]{a}=a^{\frac{1}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D)
You also need to remember the Quotient of powers property:
Therefore, you can rewrite the expression:
Finally, you have to simplify the expression. Therefore, you get:
![=2^{(\frac{1}{2}-\frac{1}{3})}\\=2^{\frac{1}{6}}\\=\sqrt[6]{2}](https://tex.z-dn.net/?f=%3D2%5E%7B%28%5Cfrac%7B1%7D%7B2%7D-%5Cfrac%7B1%7D%7B3%7D%29%7D%5C%5C%3D2%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%5C%5C%3D%5Csqrt%5B6%5D%7B2%7D)
Is this math? I'm sorry I don't get what formula I'm supposed to rewrite or -
Answer:
the question is incomplete, below is the complete question
"ress the following complex numbers in rectangular form. Show how you get the answer and use a calculator to verify your answer. E.g. 2 pts for 2∠30°=2(cos30°+jsin30°)=1.73+j, 1 pt for 2∠30°=1.73+j. Same grading criteria as 1.4. (a) Z1=5eⁱ³⁰ (b) z2=−3 ∠(−45°) (c) z3=2∠(−90°)
answer
a.Z1=4.33+j2.5
b. Z2=-2.12+j2.12
c.Z3=-2j
Step-by-step explanation
note that
Z=reⁱⁿ=r(cosπ+jsinπ)
hence from Z1=5eⁱ³⁰ wen have
Z1=5(cos30+jsin30)
Z1=5(0.8660+j0.5)
Z1=4.33+j2.5
b.also from z=r∠(π)=r(cosπ+jsinπ)
Hence,
z2=−3 ∠(−45°)=-3(cos(-45)+jsin(-45))
Z2=-3(0.7071-j0.7071)
Z2=-2.12+j2.12
c. z3=2∠(−90°)=2(cos(-90)+jsin(-90))
Z3=2(0-j)
Z3=-2j
The angle that is same side exterior angle to ∠ABC is ∠EFH.
<h3>How to find angles?</h3>
When parallel line are cut by a transversal line, angle relationships are formed such as corresponding angles, vertically opposite angles, alternate angles, same interior angles, etc.
AD and EG are parallel to each other.
CH is a transversal line to the parallel lines.
Therefore, let's find the angle that has the same relationship as same side exterior angles as angle ABC.
Two angles that are exterior to the parallel lines and on the same side of the transversal line are called same-side exterior angles.
Same side exterior angles are supplementary.
Therefore,
∠ABC and ∠EFH are same side exterior angles.
learn more on angles here: brainly.com/question/24755745
#SPJ1
