Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
Answer:
Its 4 and -4 :)
Step-by-step explanation:
Answer:
<u>9 feet 2 inches</u>
Step-by-step explanation:
Given :
⇒ Height of SUV = <u>6 feet 4 inches</u>
⇒ Height of box = <u>2 feet 10 inches</u>
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Solving :
⇒ Total Height = Height of SUV + Height of box
⇒ Total Height = 6 feet 4 inches + 2 feet 10 inches
⇒ Total Height = 8 feet 14 inches
* But, 12 inches = 1 feet *
Hence,
⇒ Total Height = 8 feet + 1 foot + 2 inches
⇒ Total Height = <u>9 feet 2 inches</u>
To find how much of 5/8 is you would need to divide 1/2 by 5/8:
X = (1/2) / (5/8)
When dividing fractions, you reverse the second fraction and multiply:
X = (1/2) x (8/5)
X = 8/10
Simplify:
X = 4/5
