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snow_lady [41]
4 years ago
11

In Rhombus AYXZ, which is 3a + 2b?

Mathematics
1 answer:
gtnhenbr [62]4 years ago
5 0
A = 58
b = 32
3 * 58 = 174
2 * 32 = 64

174 + 64 = 238


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Please help! Thank you if you do!
vekshin1

Answer:

8/50

5/50

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38/50

45/50

Step-by-step explanation:

8 0
3 years ago
1. Write a two-column proof.
Alexandra [31]

Answer:

Check it below, please

Step-by-step explanation:

Hi there!

Let's prove segment AB is perpendicular to CD. Attention to the fact that a two column proof has to be concise. So all the comments can't be exhaustive, but as short as possible.

Let's recap: An isosceles triangle is one triangle with at least 2 congruent angles.

Statement                     Reason

\overline{AB} \cong \overline{AC}\\                     Given

\widehat{ACB} \:bisects\: \overline{AB}        Isosceles Triangle the altitude, the bisector coincide.          

\overline{AD} \cong \overline{DB}               Bisector equally divide a line segment into two congruent      

m\angle CDA =m \angle CBD=90^{\circ} Right angles, perpendicular lines.                  

\overline{CD}\perp \overline{AB}                    Perpendicular Line segment      

8 0
4 years ago
If the value of third order determinant is 11. Then what is the value of the determinant formed by its cofactors.
nordsb [41]

Answer:

146.41

Step-by-step explanation:

third order determinant = determinant of 3×3 matrix A

given ∣A∣=11

det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)

=det(adjacent of A)

{det (cofactor matrix of A)}  ^2  = {det (adjacent of A)} ^2

 

(Using for an n×n det (cofactor matrix of A)=det (A)^n−1 )

we get

det (cofactor matrix of A)^2  = {det(A)  ^3−1 }^2

 

=(11)^2×2  = 11^4

 =146.41

5 0
3 years ago
A time/motion word problem
andriy [413]
The two planes are flying on the two legs of a right triangle.
The straight distance between them is the hypotenuse of the triangle.

Since the speeds are in mph, let's work the time in hours.
Call the time 'H' that we're looking for.
It's the number of hours after they both take off that they're 650 miles apart.

After 'H' hours, the first plane has gone 500H miles north.
After 'H' hours, the second plane has gone 1200H miles east.
After 'H' hours, they are 650 miles apart.

Do you remember this for a right triangle ? ==>    A² + B² = C²

(500H)² + (1200H)² = (650)²

250,000H² + 1,440,000H² = 422,500

1,690,000 H² = 422,500

H² = (422,500) / (1,690,000) = 0.25

H = √0.25 = 1/2 hour = 30 minutes
3 0
4 years ago
Read 2 more answers
Please helppppp I need help​
a_sh-v [17]

Answer:

non proportional

Step-by-step explanation:

All of the others are correct

4 0
3 years ago
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