A horizontal line has a slope of ?

Solve this system by elimination 10x+6y=14 -x-6y=-23

ludmilkaskok [199]

Answer:

(-1, 4)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define systems

10x + 6y = 14

-x - 6y = -23

Step 2: Solve for x

Elimination

Add 2 equations together: 9x = -9
Divide 9 on both sides: x = -1

Step 3: Solve for y

Define original equation: -x - 6y = -23
Substitute in x: -(-1) - 6y = -23
Multiply: 1 - 6y = -23
Subtract 1 on both sides: -6y = -24
Divide -6 on both sides: y = 4

8 0

3 years ago

stack of mail consists of 8 bills, 10 letters, and 6 advertisements. One piece of mail is drawn at random and put aside. Then a

kozerog [31]

INFORMATION:

We know that:

- stack of mail consists of 8 bills, 10 letters, and 6 advertisements.

- One piece of mail is drawn at random and put aside. Then a second piece of mail is drawn.

And we must find P (both are letters)

STEP BY STEP EXPLANATION:

To find the probability, we need to know that we have two events. First, when one piece of mail is drawn at random and put aside and, second, when a second piece of mail is drawn.

These two events are dependent. If A and B are dependent events, P(A and B) = P(A) • P(B after A) where P(B after A) is the probability that B occurs after A has occurred.

So, first

- Probability of A (the first piece is letter)

$P(A)=\frac{favorable\text{ }cases}{total\text{ cases}}=\frac{10}{24}$

- Probability of B after A

Since A already occurred and one piece of the mail was drawn (a letter), now in total we would have 9 letter and 23 total pieces

$P(B\text{ after }A)=\frac{9}{23}$

Finally, replacing in the initial formula

$P(A\text{ and }B)=\frac{10}{24}\cdot\frac{9}{23}=\frac{90}{552}=0.1630$

Finally, the probability would be 0.1630

ANSWER:

P (both are letters) = 0.1630

8 0

1 year ago

Josh can clean the math building on his campus in 2 hours. Ken takes 23 hours to clean the same building. If they work together

ANTONII [103]

Answer:

1.84 hr.

Step-by-step explanation:

7 0

3 years ago

Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe

8090 [49]

Answer:

The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

Step-by-step explanation:

Let's define:

R₁ = rate of bus 1, this is the faster one.

R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

R₂ = R₁ - 14mi/h

R₁*2h + R₂*2h = 304 mi

The first step is to replace the first equation in the second one, to get:

R₁*2h + (R₁ - 14mi/h)*2h = 304 mi

And now we can solve this for R₁.

R₁*2h + R₁*2h - 14mi/h*2h = 304 mi

R₁*4h - 28mi = 304mi

R₁*4h = 304mi + 28mi = 332mi

R₁ = 332mi/4h = 83mi/h

The faster bus moves at 83mi/h

And we know that the slower one moves at 14mi/h slower than this, then:

R₂ = R₁ - 14mi/h = 83mi/h - 14mi/h = 69 mi/h

7 0

2 years ago

Match each subtraction problem on the left with the equivalent simplified expression on the right.

Ahat [919]

Answer:

A-3, B-4, C-1, D-2

Step-by-step explanation:

A:

5x-(3x+1)
Expand, 5x-3x-1
Combine like terms, 2x-1

B:

5x-(-3x-1)
Expand, 5x+3x+1
Combine like terms, 8x+1

C:

-5x-(3x+1)
Expand, -5x-3x-1
Combine like terms, -8x-1

D:

-5x-(-3x-1)
Expand, -5x+3x+1
Combine like terms, -2x+1

4 0

3 years ago