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creativ13 [48]
2 years ago
5

In a survey of 1900 people who owned a certain type of​ car, 1140 said they would buy that type of car again. What percent of th

e people surveyed were satisfied with the​ car?
Mathematics
1 answer:
charle [14.2K]2 years ago
5 0

Answer:

60% of the people surveyed were satisfied with the car

Step-by-step explanation:

1140 satisfied people / 1900 total people = 0.60 = 60% satisfied people

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I need help quickly. I think it's B or D.
Ludmilka [50]

personally id say c cuz the one on the right makes it have no trend, and also because if it was a negative trend there should only have been one answer on it really.

5 0
3 years ago
Read 2 more answers
Solve for x rounding to nearest tenth​
Lina20 [59]
X = 13.26

here’s a photo with the work if that helps at all :)

6 0
2 years ago
The probability of a spinner landing on a 4 is 5/8. What is the probability that the spinner will land on a number other than 4?
Alja [10]
The probability that it doesn't land on 4 would be 3/8. This is because theres a 5/8 chance it lands on 4 so just do the opposite which would be 3/8. 
5 0
3 years ago
Which of the following phrases can be used to represent -11? the opposite of -11 eleven greater than zero eleven below zero posi
Rama09 [41]

Answer:

the opposite of -11 eleven greater than zero eleven below zero positive eleven

Step-by-step explanation:

5 0
3 years ago
Suppose that a function​ f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence
Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

\lim_{x \to c} \frac{x^2-cx}{(x-c)}

We can simplify it

\lim_{x \to c} \frac{x(x-c)}{(x-c)}

=\lim_{x \to c} x

=c

so, we can see that limit exist and it's value defined

case-2:

\lim_{x \to c} \frac{1}{(x-c)}

Left limit is

\lim_{x \to c-} \frac{1}{(x-c)}

=-\infty

Right Limit is

\lim_{x \to c+} \frac{1}{(x-c)}

=+\infty

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0
3 years ago
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