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3 years ago

Help please confused

Mathematics

1 answer:

dolphi86 [110]3 years ago

7 0

nevermind it's 62 i messed up but it is

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Help pls this is really confusing

Ipatiy [6.2K]

Step-by-step explanation:

so the smaller one is two right? we can divide 96 by 2 to get 48 for each one

to find the bigger we simply multiply 48 by 5 to get 240

7 0

3 years ago

Based on past experience, a telemarketing firm has found that calls to prospective customers take an average of 2.0 minutes, wit

xenn [34]

Answer: Our required probability would be 0.9641.

Step-by-step explanation:

Since we have given that

Number of hours he works a day = 8

So, Number of minutes he worked in a day = $8\times 60=480\ minutes$

Number of calls = 220

So, Average $=\bar{x}=\dfrac{480}{220}=2.18\ minutes$

Standard deviation $=s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1.5}{\sqrt{220}}=0.10$

Mean = μ = 2.0 minutes

Standard deviation = σ = 1.5 minutes

Using the normal distribution, we get that

$z=\dfrac{\bar{x}-\mu}{s}\\\\z=\dfrac{2.18-2.0}{0.10}\\\\z=1.8$

So, the probability that Albert will meet or exceed his quota would be

$P(X\leq 2.18)=P(z\leq 1.8)=0.9641$

Hence, our required probability would be 0.9641.

6 0

3 years ago

In the figure, solve for x and y.

evablogger [386]

Answer:

y=124°

x=67°

Step-by-step explanation:

For the triangle on the right

180-74-50=56°

then y= 180-56=124°

For the triangle on the middle (that small triangle)

180-85(Head opposite angles)-50=45°

x=180-45-68=67°

5 0

3 years ago

The functionâ€‹ s(t) represents the position of an object at time t moving along a line. Suppose s (3 )equals 156 and s (6 )equa

bixtya [17]

Answer: The average velocity of the object over the time interval [3,6] is 20.

Step-by-step explanation:

Since we have given that

s(3) = 156

s(6) = 216

We need to find the average velocity over the time interval [3,6].

So, average velocity becomes

$\dfrac{s(t_1)-s(t_0)}{t_1-t_0}\\\\=\dfrac{s(6)-s(3)}{6-3}\\\\=\dfrac{216-156}{3}\\\\=\dfrac{60}{3}\\\\=20$

Hence, the average velocity of the object over the time interval [3,6] is 20.

5 0

3 years ago

Write an expression that represents the area of only the red shaded region in terms of x

julsineya [31]

Answer:

(9 × 3x+7) - (5 × x+2)

Step-by-step explanation:

Red area

9 × 3x + 7

white area

5 × x+2

7 0

3 years ago