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Harlamova29_29 [7]
3 years ago
10

Smallest to largest 7/12 1/2 2/3 4/10 1/6

Mathematics
1 answer:
WINSTONCH [101]3 years ago
5 0
Smallest to largest 1/6 < 4/10 < 1/2 < 7/12 < 2/3
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What is the velocity of a car that is traveling north 290 kilometers in 5 hours?
Maksim231197 [3]

Answer:

58

Step-by-step Explanation: 290 / 5 = 58

3 0
3 years ago
Evaluate the log by thinking “3 to what power is 1/9 so log3(1/9) =
Vlad [161]

Answer:-2

Step-by-step explanation:

Log3(1/9)

Log(1/9) ➗ Log3

Log(1/3^2) ➗ Log3

Log3^(-2) ➗ Log3

-2Log3 ➗ Log3

-2(Log3 ➗ Log3)

-2

8 0
3 years ago
What can you divide a2b5 by to get a quotient of 1?
Kitty [74]

9514 1404 393

Answer:

  a^2b^5

Step-by-step explanation:

Anything divided by itself is 1.

That is, anything multiplied by its reciprocal is 1. This value (the reciprocal of the expression) is called the "multiplicative inverse." Its value is that the product of an expression and its multiplicative inverse is 1, the multiplicative identity element. (Anything times 1 is itself.)

So, to get 1 as a product, multiply by 1/(a^2b^5), which is to say, divide by a^2b^5 to get 1 as a quotient.

8 0
2 years ago
A box contains 2 dozen pairs of contact lenses ,of which 8 pairs are tinted. A pair of contact lenses is drawn at random from th
tia_tia [17]

Answer:

\dfrac{2}{3}.

Step-by-step explanation:

It is given that a box contains 2 dozen pairs of contact lenses ,of which 8 pairs are tinted.

1 dozen = 12 units

Total pairs of contact lenses =2\times 12 = 24

Tinted pairs of contact lenses = 8

Pairs of contact lenses not tinted = 24 - 8 = 16

If a pair of contact lenses is drawn at random from the box, then we need to find the probability that it is not tinted.

P(\text{Not tinted})=\dfrac{\text{Pairs of contact lenses not tinted}}{\text{Total pairs of contact lenses}}

P(\text{Not tinted})=\dfrac{16}{24}

P(\text{Not tinted})=\dfrac{2}{3}

Therefore, the required probability is \dfrac{2}{3}.

4 0
3 years ago
Find the missing side lengths. Leave your answers as radicals in simplest form.
Citrus2011 [14]

This is the isosceles right triangle, the diagonal of a square, the thing that so upset the Pythagoreans. The two sides and diagonal of a square are in ratio 1:1:\sqrt{2} so we get


u = v =  8


We could have also gotten this using Trig:


u = (8 \sqrt{2}) \sin 45^\circ = 8 \sqrt{2}/\sqrt{2} = 8


v = (8\sqrt{2})\cos 45^\circ = 8


Or by recognizing u=v because remaining angle is 45 so this must be isosceles so


u^2 + u^2 = (8 \sqrt{2})^2


2u^2 = 2 (8^2)


u = 8

8 0
3 years ago
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