Answer:
Number of electron on the fur will be 
Explanation:
We have given net charge on the fur 
Charge on one electron 
Let there are n number of electrons
So 


So number of electron on the fur will be 
Answer:The thymus stores and produces T lymphocytes and also releases hormones which aid in the maturation of the T lymphocytes while the spleen stores and release lymphocytes as well as macrophages which eradicate foreign substances that may harm the body.
Explanation:
Answer:
Number of days needed = 57
Explanation:
Depth of well = 115 feet
Distance traveled in day = 3 feet up
Distance traveled in night = 1 feet down.
Total displacement in 1 day = 3 - 1 = 2 feet up
When the snail reaches 112 feet up, the next 3 feet up motion on day will make it reach the top.

After 56 days the displacement of snail is 112 feet.
On the next day it moves up by 3 feet and reaches out of well.
Number of days needed = 57
The frequency of a tuning fork that takes2.50×10⁻³ s to complete one oscillation would be 400 Hz.
<h3>What is the frequency?</h3>
It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.
As given in the problem a tuning fork takes 2.50×10⁻³ s to complete one oscillation.
Frequency = 1/time period of the oscillation
Frequency of the tuning fork = 1/time period
=1/2.50×10⁻³
=400 Hz
Thus the frequency of a tuning fork comes out to be 400 Hz.
Learn more about frequency here, refer to the link;
brainly.com/question/14316711
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Answer:
a = R/2
Explanation:
Let R be the radius of the sphere and q = -2e be the charge in it. Let q₁ be the charge at radius a where the one of the point positive charges e is located. . Since the charge is uniformly distributed, the volume charge density is constant. So, q/4πR³ = q₁/4πa³
q₁ = q(a/R)³ = -2e(a/R)³. The electric force due to q₁ at r is F₁ = kq₁q/a² = kq²(a/R)³/a² = k(-2e)²a/R³ = 4ke²a/R³.
Let h be the distance between the two point charges. The electric force due to the one point charge on the other is F₂ = ke²/h²
If the net force on either charge is zero, then
F₁ = F₂
4ke²a/R³ = ke²/h²
a = R³/4h²
Since h = 2a, since the charges are equidistant from each other,
a = R³/4(2a)² = R³/8a²
a = R³/8a²
a³ = R³/8
a = ∛(R³/8)
a = R/2