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3 years ago

The material through which a mechanical wave travels is a.a medium.b.empty space.c.ether.d.air

Physics

1 answer:

Elza [17]3 years ago

5 0

<h2>Answer: Medium </h2>

The medium is the main factor that differentiates a mechanical wave from an electromagnetic wave, since the first can not propagate without its existence, while the second can propagate regardless of whether the medium exists or not.

In addition, it is the medium that will define, the propagation speed of the wave, according to its specific physical characteristics.

Therefore, the <u>correct answer</u> is a.

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A piece of amber is charged by rubbing with a piece of fur. If the net excess charge on the fur is +8.0 nC (+8.0 10-9 C), how ma

Ann [662]

Answer:

Number of electron on the fur will be $5\times 10^{10}electron$

Explanation:

We have given net charge on the fur $q=8nC=8\times 10^{-9}C$

Charge on one electron $e=1.6\times 10^{-19}C$

Let there are n number of electrons

So $ne=8\times 10^{-9}$

$n\times 1.6\times 10^{-19}=8\times 10^{-9}$

$n=5\times 10^{10}electron$

So number of electron on the fur will be $5\times 10^{10}electron$

6 0

3 years ago

Compare and contrast the function of the thymus and spleen<br> needed asap

Helga [31]

Answer:The thymus stores and produces T lymphocytes and also releases hormones which aid in the maturation of the T lymphocytes while the spleen stores and release lymphocytes as well as macrophages which eradicate foreign substances that may harm the body.

Explanation:

6 0

3 years ago

A snail is at the bottom of a well, 115 feet deep. On day 1, it starts climbing up the side. That night it rests and slips down

julia-pushkina [17]

Answer:

Number of days needed = 57

Explanation:

Depth of well = 115 feet

Distance traveled in day = 3 feet up

Distance traveled in night = 1 feet down.

Total displacement in 1 day = 3 - 1 = 2 feet up

When the snail reaches 112 feet up, the next 3 feet up motion on day will make it reach the top.

$\texttt{Days to travel 112 feet up = }\frac{112}{2}=56$

After 56 days the displacement of snail is 112 feet.

On the next day it moves up by 3 feet and reaches out of well.

Number of days needed = 57

4 0

3 years ago

Find the frequency of a tuning fork that takes2.50×10−3s to complete one oscillation.

maksim [4K]

The frequency of a tuning fork that takes2.50×10⁻³ s to complete one oscillation would be 400 Hz.

<h3>What is the frequency?</h3>

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

As given in the problem a tuning fork takes 2.50×10⁻³ s to complete one oscillation.

Frequency = 1/time period of the oscillation

Frequency of the tuning fork = 1/time period

=1/2.50×10⁻³

=400 Hz

Thus the frequency of a tuning fork comes out to be 400 Hz.

Learn more about frequency here, refer to the link;

brainly.com/question/14316711

#SPJ1

6 0

2 years ago

Consider a simple but surprisingly accurate model for the hydrogen molecule: two positive point charges, each having charge e, a

lyudmila [28]

Answer:

a = R/2

Explanation:

Let R be the radius of the sphere and q = -2e be the charge in it. Let q₁ be the charge at radius a where the one of the point positive charges e is located. . Since the charge is uniformly distributed, the volume charge density is constant. So, q/4πR³ = q₁/4πa³

q₁ = q(a/R)³ = -2e(a/R)³. The electric force due to q₁ at r is F₁ = kq₁q/a² = kq²(a/R)³/a² = k(-2e)²a/R³ = 4ke²a/R³.

Let h be the distance between the two point charges. The electric force due to the one point charge on the other is F₂ = ke²/h²

If the net force on either charge is zero, then

F₁ = F₂

4ke²a/R³ = ke²/h²

a = R³/4h²

Since h = 2a, since the charges are equidistant from each other,

a = R³/4(2a)² = R³/8a²

a = R³/8a²

a³ = R³/8

a = ∛(R³/8)

a = R/2

7 0

3 years ago