Answer:
The frequency of infrared wave is 35.385 GHz
Explanation:
Given data:
Wavelength of infrared light = 8.45 mm = 8.45 x
m
Velocity of infrared light = 2.99 x
m/s
To find: frequency of the infrared wave = ?
We know that the wavelength and frequency are inversely proportional and the formula to derive frequency with velocity and wavelength is:
c = μλ, where
c is velocity of light
μ is frequency of light
λ is wavelength of light
Hence the frequency of light μ = c/λ
= 
=
x

= 35.385 x
Hz (since 1
= 1 Hz)
= 35.385 GHz
Answer:
A microchip in the phone modulates (or varies) a radio wave using the electrical signal. The radio wave travels through the air to a nearby cell tower; the tower sends your voice to the person you are calling and the process is reversed so that the person on the other end can hear your voice.
Please Mark Brainliest If This Helped!
Answer:
True
Explanation:
If we swing a bucket of water fast enough in a vertical circle the water does not spill out even at the top-most position of the bucket. This happens because the centrifugal force acting away from the center in a circular motion neutralizes or overcomes the gravitational force on the water particles.
<u>Centrifugal force is mathematically related as:</u>

where:
m = mass of the revolving body
r = radius of revolution
angular velocity in radians per second
This force F acts in radially outward direction.
<span>Customers would not get electricity. If the transmission lines [heavy power] leaving the plant broke [zap], it's just fix the transmission lines. But if the generators or main switch gear were lost, so the plant itself has no power, it can get ugly. </span>
Answer:
<em>t=14.96 sec</em>
Explanation:
<u>Diagonal Launch
</u>
It's a physical event that happens where an object is thrown in free air (no friction) forming an angle with the horizontal reference. The object then describes a path called a parabola.
The object will reach its maximum height and then return to the height from which it was launched. The equation for the height is
:

Where vo is the initial speed,
is the angle, t is the time and g is the acceleration of gravity
.
In this problem we'll assume the arrow was launched from the ground level (won't consider the archer's height). Thus
, and:

The value of y is zero twice: when t=0 (at launching time) and in t=
when it goes back to the ground. We need to find that time
by making

Dividing by 

Then we find the total flight time as

