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alexdok [17]
3 years ago
7

The distance from the Earth to the Sun is known as an astronomical unit (AU). This distance is also equal to 1.496e+011 m. Neptu

ne has an orbit with an average diameter of 8.80e+009 km. What is the distance from the Sun to Neptune in AU?
A. 24.5 AU
B. 36.3 AU
C. 29.4 AU
D. 68.5 AU
E. 55.8 AU
Physics
1 answer:
Lerok [7]3 years ago
7 0

Answer:

The distance from the Sun to Neptune is 29,41 AU.

Explanation:

We know, from the sentence, that the orbit of Neptune has an average diameter around 8.80*10⁹km.

Now, we can calculate the radius of this orbit, which is equivalent to the distance from thsi planet to the Sun. Let's recall tha the radius is the half of the diameter.

R=\frac{8.80\cdot 10^{9}}{2}=4.4\cdot 10^{9}km=4.4\cdot 10^{12}m

Ok, we know that 1.496*10¹¹m is an AU, therefore we have:

4.4\cdot 10^{12}m\cdot \frac{1 AU}{1.496\cdot 10^{11}}=29,41 AU

Finally, the distance R is 29,41 AU.

I hope it helps you! :)

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Answer:

38.47 m

Explanation:

To find the height of the building, we will use the following equation

y_f=y_i+v_{iy}t+\frac{1}{2}at^2

Where yf is the final height, yi is the initial height, viy is the initial vertical velocity, t is the time, and a is the acceleration due to gravity.

If the brick is in flight for 3.1 s, we can say that when t = 3.1s, yf = 0 m. So, replacing

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we get

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Solving for yi

\begin{gathered} 0=y_i-38.48 \\ y_i=38.48\text{ m} \end{gathered}

Therefore, the height of the building is 38.48 m

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