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alexdok [17]
3 years ago
7

The distance from the Earth to the Sun is known as an astronomical unit (AU). This distance is also equal to 1.496e+011 m. Neptu

ne has an orbit with an average diameter of 8.80e+009 km. What is the distance from the Sun to Neptune in AU?
A. 24.5 AU
B. 36.3 AU
C. 29.4 AU
D. 68.5 AU
E. 55.8 AU
Physics
1 answer:
Lerok [7]3 years ago
7 0

Answer:

The distance from the Sun to Neptune is 29,41 AU.

Explanation:

We know, from the sentence, that the orbit of Neptune has an average diameter around 8.80*10⁹km.

Now, we can calculate the radius of this orbit, which is equivalent to the distance from thsi planet to the Sun. Let's recall tha the radius is the half of the diameter.

R=\frac{8.80\cdot 10^{9}}{2}=4.4\cdot 10^{9}km=4.4\cdot 10^{12}m

Ok, we know that 1.496*10¹¹m is an AU, therefore we have:

4.4\cdot 10^{12}m\cdot \frac{1 AU}{1.496\cdot 10^{11}}=29,41 AU

Finally, the distance R is 29,41 AU.

I hope it helps you! :)

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(35 miles) x (the number of hours since it started traveling).

At some points during that time, the car was most likely moving
faster or slower than 35 miles per hour.  We don't know.  We only
know that it covered  (35 miles) x (the number of hours since it left).
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3 years ago
A cubical wooden box floating on water rises 1cm when 400 gm of stone is
Ksivusya [100]

Answer:

Explanation:

I'm not  sure you can do this without just a bit more information. I can tell you what the mass of the water is when the rocks are removed. When we know that, we know the volume of the water that was displaced. whether or not this is enough information to determine the volume of the box, I'm not sure.

400 grams raises the box 1 cm.

The density of water = 1 gm / cm^3

400 grams of water = 400 mL or 400 cm^3

The volume of the displaced water = 400 cm^3

The volume a slice from the square prism is B*h

B = 400 cm^2

h = 1 cm

If the base is 400 cm^2 then each side is

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sqrt(s^2)= sqrt(400)

s = 20

The volume of the box is 20^3 = 8000 cm^3

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g Suppose that you charge a 3 F capacitor in a circuit containing eight 3.0 V batteries, so the final potential difference acros
Vladimir79 [104]

The complex, highly technical formula for capacitors is

<em>Q = C V</em>

Charge = (capacitance) (voltage)

Charge = (3 F) (24 V)

<em>Charge = 72 Coulombs</em>

The positive plate of the capacitor is missing 72 coulombs worth of electrons.  They were sucked into positive terminal of the battery stack.

The negative plate of the capacitor has 72 coulombs worth of extra electrons.  They came from the negative terminal of the battery stack.

You should be aware that this is a humongous amount of charge !  An average <u><em>lightning bolt</em></u>, where electrons flow between a cloud and the ground for a short time, is estimated to transfer around <u><em>15 coulombs</em></u> of charge !

The scenario in the question involves a "supercapacitor".  3 F is is no ordinary component ... One distributor I checked lists one of these that's able to stand 24 volts on it, but that product costs $35 apiece, you have to order at least 100 of them at a time, and they take 2 weeks to get.  

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7 0
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Suppose the sphere is electrically neutral. Is it attracted to
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Answer:

No, it is not attracted.

Explanation:

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The vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

The given parameters;

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The components of the velocity can be horizontal or vertical velocity.

The vertical component of the velocity is affected by acceleration due to gravity while the horizontal component of the velocity is not affected by gravity.

The vertical component of the velocity is calculated as;

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The horizontal component of the velocity = 16 m/s

Thus, the vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

Learn more here:brainly.com/question/20349275

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