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Svetradugi [14.3K]
2 years ago
12

A project is graded on a scale of 1 to 5. If the random variable, X, is the project grade, what is the mean of the probability d

istribution below?
                     Probability Distribution

.45    |
.4      |                            ~
.35    |                            ~
.3      |                            ~
.25    |                            ~
.2      |                ~          ~          ~
.15     |                ~          ~          ~
.1       |    ~          ~          ~          ~          ~
.05    |    ~          ~          ~          ~          ~
0       |__~____~_____~_____~____~____
              1          2          3          4          5
                                 X
Answer Choices:  A. 0.2  B. 0.4   C. 1  D. 3
Mathematics
2 answers:
choli [55]2 years ago
8 0

The correct answer is D) 3.

The mean is 3

damaskus [11]2 years ago
5 0

Answer:

3

Step-by-step explanation:

Given that A project is graded on a scale of 1 to 5.

If the random variable, X, is the project grade, we have to find  the mean of the probability distribution below

Since X takes values as 1,2,3,4,5

from the picture given we find the frequency distribution of X

X    1    2     3     4    5     Total

f     2    4     8     4    2       20

fx    2    8    24   16  10      60

Mean =60/20 =3

Hence answer is 3

   

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A quantity with an initial value of 600 decays exponentially at a rate of
Snowcat [4.5K]

Answer:

The value of the quantity after 87 months will be of 599.64.

Step-by-step explanation:

A quantity with an initial value of 600 decays exponentially at a rate of 0.05% every 6 years.

This means that the quantity, after t periods of 6 years, is given by:

Q(t) = 600(1 - 0.0005)^{t}

What is the value of the quantity after 87 months, to the nearest hundredth?

6 years = 6*12 = 72 months

So 87 months is 87/72 = 1.2083 periods of 6 years. So we have to find Q(1.2083).

Q(t) = 600(1 - 0.0005)^{t}

Q(1.2083) = 600(1 - 0.0005)^{1.2083} = 599.64

The value of the quantity after 87 months will be of 599.64.

8 0
3 years ago
What is 5.476 rounded to the hundredths
ddd [48]
5.476 rounded to the hundrdths is 

5.48
7 0
3 years ago
Read 2 more answers
The average salary for a construction worker is $29,160 per year. A veterinarian makes on average $84,460. If you consider the e
Bad White [126]
55,300 difference that is the answer
6 0
2 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
2 years ago
25,000 bricks were used to build the new library. The total weight of the bricks was 30,000 pounds. What is the weight of each b
Lelechka [254]
I would go with 1.2 pounds
4 0
2 years ago
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