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enot [183]
3 years ago
5

Which of the following polygons can form a regular tessellation?

Mathematics
1 answer:
Ksju [112]3 years ago
7 0

Answer:

A

Step-by-step explanation:

A

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Tony wants to purchase a baseball glove for $14.96, a baseball bat for $19.87, and a baseball for $5.37. He figured out that he
Vanyuwa [196]
Reasonable because the three items altogether cost about $40
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3 years ago
If you have a spinner with 5 slots, what is the compound probability of spinning an even number, then an odd number? Expressed a
Minchanka [31]

Since the spinner has 5 slots it contains 3 odd and 2 evens,

  • Odds ⇒ 1, 3, 5
  • Evens⇒ 2,4

this can be expressed as

\frac{2}{5} =\frac{x}{100}, cross multiply and we get

5x=200

x=40%

6 0
2 years ago
Read 2 more answers
Identify the variation as direct, inverse, joint or combined.
Inessa [10]
<span>a. direct variation
A relationship between two variables in which one is a constant multiple of the other. </span>
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3 years ago
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What is the surface area of the<br> rectangular prism below?
Vikki [24]

To Find Surface Area:

So Surface area is found according to this equation SA=2lw+2lh+2hw

6and 1/2 times 2 is 13 that would be the 2 sides

then you do 3 times 6 1/2 which is 19 1/2, which is the top and bottom

finally you do 3 times 9 1/5 which is 27 3/5.

Now since 1/2 and 1/5 are not the same, we find the LCM or Least Common Multiple, which is 10 so 1/2 is multiplied by 5 which is 5/10 and 3/5 is multiplied by 2 which makes 6/10.

Adding 5/10 and 6/10 is 11/10 or 1 1/10

13+6+9=28

28+1 1/10 = 29 1/10

and finally because we did surface area it is 29 1/10 CM^2

__________________________________________________________

To Find Volume:

The Equation used to find volume is l*w*h

The Length is 6 1/2

Height is 9 1/5

width is 3

First, lets again convert the fractions

5/10 and 6/10

6 5/10 times 9 6/10 is 62.4

62.4 times 3 is 187.2

The .2 and be put into 2/10 or 1/5  so the FINAL answer is 187 1/5

Another way to check this is

6*9*3=162

1/5*1/2

Hope this helped :)

~Ukiahsmith1

5 0
3 years ago
Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando
Korolek [52]

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = \frac{7}{13}

For $5 bill, expected value = \frac{1}{13}

For $10 bill, expected value = \frac{3}{13}

For $20 bill, the expected value = \frac{2}{13}

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

6 0
3 years ago
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