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kramer
3 years ago
10

Solve x2 + 2x + 9 = 0

Mathematics
2 answers:
Keith_Richards [23]3 years ago
8 0
x^2+2x+9=0 \\ \\
a=1 \\ b=2 \\ c=9 \\ b^2-4ac=2^2-4 \times 1 \times 9=4-36=-32 \\ \\
x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-2 \pm \sqrt{-32}}{2 \times 1}=\frac{-2 \pm \sqrt{-16 \times 2}}{2}=\frac{-2 \pm 4i\sqrt{2}}{2}=-1 \pm 2i\sqrt{2}

The answer is D.
Ksenya-84 [330]3 years ago
4 0
x^{2}+2x+9=0 \\  \\ x^{2}+2x+1+8=0 \\  \\ (x+1)^{2}+(2 \sqrt{2})^{2}=0  \\  \\ (x+1+2 \sqrt{2}i)(x+1-2 \sqrt{2}i)=0   \\  \\ x+1+2 \sqrt{2}i=0 \ \vee \ x+1-2 \sqrt{2}i=0 \\  \\ x=-1-2 \sqrt{2}i \ \vee \ x=-1+2 \sqrt{2}i

==========================

a^{2}+b^{2}=(a+bi)(a-bi)
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Step-by-step explanation:

We are given the function:

\displaystlye F(x) = x^2 - 2x + 4

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We can substitute:

\displaystyle F(b + 3) = (b + 3)^2 - 2(b+3) + 4

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