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ch4aika [34]
3 years ago
5

8. If you were going to use the quadratic formula to solve the following equation and a = 9, what number would you use as the va

lue for the variable 'b'? 3x + 8 = 9x2 The variable 'b' = ____. (4.0 Points) Part 9 - - 0/1 Answered Questions, 4.0 Points
Mathematics
1 answer:
ludmilkaskok [199]3 years ago
4 0

Answer:

Remember, for solve the quadratic equation

ax^2+bx+c=0

we use the quadratic formula

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

We have the equation 3x+8=9x^2 since a must be 9 then we pass the entire left side of the equation to the right side. We get the equation:

3x+8=9x^2\\8=9x^2-3x\\0=9x^2-3x-8

Then, observe that a=9 and b=-3

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Subtract 15 from 45 and divide by 3​
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Answer:

10

Step-by-step explanation:

45-15=30

30/3=10

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Write an expression that uses partial products to multiply 8× 64
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Use the Euclidean Algorithm to demonstrate that 621 and 82 are relatively prime to each other. Explain.
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Answer:

621 and 82 are relatively prime.

Step-by-step explanation:

Two integers are relatively prime (or coprime) if there is no integer greater than one that divides them both (that is, their greatest common divisor is one).

The greatest common divisor of two integers <em>a</em> and <em>b</em> is the largest integer that divides them both.

The Euclidean algorithm is an efficient method for computing the greatest common divisor of two integers, without explicitly factoring the two integers.

The Euclidean algorithm solves the problem:

<em>Given integers a, b find </em>d=gcd(a,b)<em />

The Euclidean algorithm provides a fast way to determine <em>d</em> without knowing the prime factors of <em>a</em> or <em>b</em>. Here is an outline of the steps:

  1. Let a=x, b=y
  2. Given <em>x</em>, <em>y</em>, use the division algorithm to write x=yq+r, \quad 0\leq r\leq |y|.
  3. If r = 0, stop and output <em>y</em>; this is the gcd of a, b.
  4. If r \neq 0, replace (<em>x, y</em>) by (<em>y, r</em>). Go to step 2.

The division algorithm is an algorithm in which given 2 integers N and D, it computes their quotient Q and remainder R.

Let's say we have to divide N (dividend) by D (divisor). We will take the following steps:

Step 1: Subtract D from N repeatedly until we get a result that lies between 0 (inclusive) and D (exclusive) and is the smallest non-negative number obtained by repeated subtraction.

Step 2: The resulting number is known as the remainder R, and the number of times that D is subtracted is called the quotient Q.

Applying the above steps,

621-82=539\\539-82=457\\457-82=375\\375-82=293\\293-82=211\\211-82=129\\129-82=47\\\\621=82\cdot7+47

621 = 82\cdot 7 + 47\\ 82 = 47\cdot 1 + 35\\ 47 = 35\cdot1 + 12\\ 35 = 12\cdot2 + 11\\ 12 = 11\cdot1 + 1\\ 11 = 1\cdot11 + 0

The gcd(621, 82) is 1. Therefore, 621 and 82 are relatively prime.

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