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AVprozaik [17]
3 years ago
6

20 Points + Brainliest for the answer and Explanation!!!

Mathematics
1 answer:
Vlad1618 [11]3 years ago
8 0

Answer:

P+Q=5x^2+4

Q-P=-x^2-4x+16

Step-by-step explanation:

We are given

P=3x^2+2x-6

Q=2x^2-2x+10

Calculation of P+Q:

P+Q=3x^2+2x-6+2x^2-2x+10

now, we can combine like terms

P+Q=3x^2+2x^2+2x-2x+10-6

P+Q=5x^2+0+4

P+Q=5x^2+4

Calculation of Q-P:

Q-P=2x^2-2x+10-(3x^2+2x-6)

Firstly, we will distribute negative sign

Q-P=2x^2-2x+10-3x^2-2x+6

now, we can combine like terms

Q-P=2x^2-3x^2-2x-2x+6+10

Q-P=-x^2-4x+16

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The domain of a function is the set of values of x for which a value of y exists. In this case, the only way that a value of y would not exist is for a denominator to equal to zero. If this function is f(x) = 1/(x+1) + 5, then we must find the values of x for which the denominator (x+1) = 0, which is at x = -1.
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