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3 years ago

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A single point charge is placed at the center of an imaginary cube that has 19 cm long edges. The electric flux out of one of th

e cube's sides is -2.5 kN·m2/C. How much charge is at the center? .................. nC

1 answer:

OverLord2011 [107]3 years ago

3 0

Answer:

The amount of charge at the center is -132.7 nC

Solution:

As per the question:

Electric flux from one face of cube, $\phi_{E} = - 2.5 kN.m^{2}/C$

Edge, a = 19cm

Since, a cube has six faces, thus total flux from all the 6 faces = $6\times (-2.5) = - 15 kN.m^{2}/C$

Also, from Gauss' law:

$\phi_{E,net} = \frac{1}{\epsilon_{o}}Q_{enc}$

$Q_{enc} = 8.85\times 10^{- 12}\times - 15\times 10^{3}$

$Q_{enc} = - 132.7 nC$

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The very first thing we must do in order to solve this problem is to find an equation for the simple harmonic motion of the given particle. Simple harmonic motion can be modeled with the following formula:

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since we need to find the speed of the particle at that time, we will need to get the derivative of the equation that represents the particle's position, so we get:

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which simplifies to:

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