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vodomira [7]
3 years ago
7

A single point charge is placed at the center of an imaginary cube that has 19 cm long edges. The electric flux out of one of th

e cube's sides is -2.5 kN·m2/C. How much charge is at the center? .................. nC
Physics
1 answer:
OverLord2011 [107]3 years ago
3 0

Answer:

The amount of charge at the center is -132.7 nC

Solution:

As per the question:

Electric flux from one face of cube, \phi_{E} = - 2.5 kN.m^{2}/C

Edge, a = 19cm

Since, a cube has six faces, thus total flux from all the 6 faces = 6\times (-2.5) = - 15 kN.m^{2}/C

Also, from Gauss' law:

\phi_{E,net} = \frac{1}{\epsilon_{o}}Q_{enc}

Q_{enc} = 8.85\times 10^{- 12}\times - 15\times 10^{3}

Q_{enc} = - 132.7 nC

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high frequency sound waves have a shorter wavelength and a higher A. amplitude B. pitch C. wavelength? than low frequency sound
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if a cyclist is travelling a road due east at 12km/h and a wind is blowing from south-west at 5km/h. find the velocity of the wi
slamgirl [31]

Answer:

The velocity of wind with respect to cyclist is -15.5 \widehat{i} - 3.5 \widehat{j}.

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speed of cyclist = 12 km/h east

speed of wind = 5 km/h south west

Write the speeds in the vector form

\overrightarrow{vc} = 12 \widehat{i}\\\\overrightarrow{vw} = - 5 (cos 45 \widehat{i} + sin 45 \widehat{j})\\\\\overrightarrow{vw} =-3.5 \widehat{i} - 3.5 \widehat{j}

The velocity of wind with respect to cyclist is

\overrightarrow{vw} =-3.5 \widehat{i} - 3.5 \widehat{j}\overrightarrow{v_(w/c)} = \overrightarrow{vw}-\overrightarrow{vc}\\\\\overrightarrow{v_(w/c)} = - 3.5 \widehat{i} - 3.5 \widehat{j}  - 12 \widehat{i}\\\\\overrightarrow{v_(w/c)} =-15.5 \widehat{i} - 3.5 \widehat{j}

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3 years ago
The cannon on a battleship can fire a shell a maximum distance of 36.0 km.
Paraphin [41]

(a)The initial velocity of the shell will be 594.27 m/sec

(b)The maximum height it reaches will be 9000 m.

c)101.249 m meters lower will its surface be 36.0 km from the ship along a horizontal line parallel to the surface of the ship.

d)The error could be significant compared to the size of a target. Option C is correct.

<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

m is the mass of the block = Kg.

u is the initial velocity of fall = m/sec

h is the distance of fall =  m

g is the acceleration of free fall = m/sec²

v is the hitting velocity of =?

a)

The range of the projectile is;

\rm R = \frac{u^2 sin 2 \theta }{g} \\\\ 36 \times 10^ 3 = \frac{U^2 sin 45^0}{9.81} \\\\ U= 594.27  \ m/sec

b)

The maximum height of the projectile is;

\rm H = \frac{u^2 sin 2 \theta }{2g} \\\\ H = \frac{(594.27)^2\times (sin 45)^2}{2 \times 9.81 } \\\\ H = 9000 \ m

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The distance between its surface and the ship, measured in a horizontal arc parallel to the surface, will be 36.0 kilometers. The distance from the lower surface is found as;

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d)

An error is a mistaken or erroneous action. In some contexts, an error is interchangeable with a mistake.

The difference between the calculated value and the original value is known as the error. The inaccuracy may be large in comparison to the target's size. Option C is correct.

Hence the initial velocity of the shell, maximum height, and the distance from the lower surface will be 594.27 m/sec,9000 m, and 101.249 m and option c for question d are correct respectively.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

#SPJ1

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Friction is useful in that:

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