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Serhud [2]
3 years ago
15

Which of the following steps were applied to ABCD to obtain A'B'C'D?

Mathematics
1 answer:
Llana [10]3 years ago
4 0
Move ABCD 3 units to the left and 2 units up. (x-3, y+2)
You might be interested in
Which equation represents a line that passes through (-2, 4) and has a slope of 2/5
Ulleksa [173]

Answer:

The equation of line is 5(y-4) = 2( x+2)

2 x-5 y+24=0

Step-by-step explanation:

<u>Step 1:-</u>

Given slope is m = \frac{2}{5} and passes through (-2,4)

y-y_{1}= m(x-x_{1} )

y-4 = \frac{2}{5}(x-(-2))

5(y-4) = 2( x+2)

2 x-5 y+24=0

8 0
3 years ago
A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer
pshichka [43]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

Z_{o.o5}= -1.648

You reverse the standardization using the formula Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

-1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 7.72ounces

The lower control point will be 7.72 ounces.

The upper value will be:

Z_{0.95}= 1.648

1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 8.28ounces

The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

P(Z≤7.11)- P(Z≤0.70)= 1 - 0.758= 0.242

There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

b. For this item μ= 8.7, the control limits do not change:

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

P(Z≤-2.45)- P(Z≤-5.71)=0.007 - 0= 0.007

There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

5 0
3 years ago
Read 2 more answers
What is the value of x in the product of powers below?
sashaice [31]

Mmm, x is equals to -7....

8 0
3 years ago
X-2/x+4=x-6/x-4 how to solve ? <br> a. x=8 <br> b. x=3<br> c. x=9 <br> d. x=5
lana66690 [7]

Answer:

the answer is a where x=8

Explanation:

cross multiplication method

8 0
3 years ago
R.
Furkat [3]

Answer: A IS CORRECT

Step-by-step explanation:

6 0
3 years ago
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