Answer:
■Gene sequences would be used to make Probes for both the Southern and Northern blots.
■The probes will be used to view the presence of each gene with the use of isolated genomic DNA obtained from the isolated bacterium
■Each probes hybridized to the genome shows the pathway is isolated and point of the genes were involved in the substrate catabolism
■The carbon source in the isolate is derived from the substrate inducing the catabolic pathway as RNA determine transcripts present
■Probes hybridizing to the same sequences would be used to determine the gene activity for the pathway as seen in the southern one
■since all the genes present in the genome couldn't be identified, the northern would be important to work on
■Catabolic pathway is determined by the same genes. Hence, the need for gene/transcript probes to hybridize to the transcriptome.
The pH scale is a logarithmic one, meaning that each pH unit has 10 times as many hydrogen ions as the unit above it. So, at pH 4, there are 10 times more hydrogen ions than at pH 5 and 100 times more hydrogen ions than at pH 6.
Photosynthesis takes place
Answer:
technology has helped make the daily lives of people easer. it has also caused lost of problems such as using up all of the fossil fuels. it has also let to pollution and global warming.
Explanation:
Answer:
25%
Explanation:
<u>Genotypes and phenotypes:</u>
- SS = straight hair
- CC= curly hair
- SC = wavy hair
- AA or A0= type A blood
- BB or B0= type B blood
- AB = type AB blood
- 00 = type 0 blood
A man with straight hair and A blood has the genotype SS AA or SS A0.
A woman with wavy hair and B blood has the genotype SC BB or SC B0.
Their first child has straight hair and O blood: SS 00
Because the child has type 0 blood, both parents must have a 0 allele, so their genotypes are SS A0 and SC B0.
<u>If their second child is a boy with straight hair, what is the probability that he has A blood?</u>
The hair and blood type genes are independent, so the hair phenotype of the child is irrelevant to determine the probability of him having A blood.
The parental cross for blood type is A0 x B0.
If you do a Punnett Square, you'll get the following offspring:
25% AB, 25% B0, 25% A0 and 25% 00.
The answer is the child has a probability of 25% of having A blood.
