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lara [203]
3 years ago
13

Find the percent of decrease if 110 is decreased to 88 A) 125% B)80% C)20%

Mathematics
2 answers:
il63 [147K]3 years ago
6 0
C is correct which is 20%
stich3 [128]3 years ago
4 0

Hey there! I'm happy to help!

We have 110 minus a certain percent of 110 equals 88. Let's call this percent p and solve.

110-110p=88

We subtract 110 from both sides.

-110p=-22

We divide both sides by 110.

p=0.2

Therefore, the percent decrease is C) 20%.

Have a wonderful day! :D

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Step-by-step explanation:

Principal= $23000

Rate=6%

Time= 10years

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= 23000×6×10 / 100

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Test the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test. Upper H 0​: pequals0.6 versus U
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Answer:

Step-by-step explanation:

From the given information:

The null and the alternative hypothesis can be well written as:

H_o:P=0.6

H_1:P>0.6

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n = 200

x = 135

Alpha ∝ = 0.05 level of significance

Then;

⇒ n \times p\times (1-P)

= 200 × 0.6 × (1 -0.6)

= 200 × 0.6 × 0.4

= 48 ≥ 10

The sample proportion \hat P = \dfrac{x}{n}

= \dfrac{135}{200}

= 0.675

The test statistics Z = \dfrac{\hat P - P}{\sqrt{ \dfrac{P(1-P)}{n} }}

Z = \dfrac{0.675 - 0.6}{\sqrt{ \dfrac{0.6 \times 0.4}{200} }}

Z = \dfrac{0.075}{\sqrt{ \dfrac{0.24}{200} }}

Z = 2.165

The P-value = P(Z > 2.165)

= 1 - P(Z < 2.165)

From the z tables

= 1 - 0.9848

= 0.0152

Reject the null hypothesis since P-Value is lesser than alpha. ( i.e. 0.0152 < 0.05).

Thus, there is enough evidence to conclude that the value of the population proportion is greater than 0.6

7 0
3 years ago
The population of a town increases at a rate of 5% every year. The population of this town was 10,400 in 2017. What will the pop
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Answer:

The population of the town in 2020  will approx. be 12,039.

Step-by-step explanation:

The initial population in the year 2017 = 10,400

Increase in population every yea r  =  5%

Now, 5% of 10, 400 = \frac{5}{100} \times 10, 400 = 520

Hence, the population in the year 2018 = 10,400 + 520 = 10,920

Now, in the year 2019

5% of 10, 920 = \frac{5}{100} \times 10, 920 = 546

Hence, the population in the year 2019 = 10,920 + 546 = 11,466

Now, in the year 2020

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or, the population in the year 2020 = 11,466  + 573.3 = 12,039.3

The population of the town in 2020  will approx. be 12,039.

6 0
3 years ago
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Answer:

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7 0
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Read 2 more answers
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