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Shalnov [3]
3 years ago
14

Why do scientists ask questions?

Physics
2 answers:
aleksandrvk [35]3 years ago
8 0
To clear their doubts and make/discover new things

andrezito [222]3 years ago
4 0
Scientists ask questions so that they can be answered. As well as solving the world and its mysteries
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\a stone is dropped from the top of a cliff. it hits the ground below after 3.80s. how high is the cliff in meters?
OlgaM077 [116]
No velocity ws given? let's use
H= ½gt²
H= ½×10×3.8
H= 19m
6 0
4 years ago
Suppose you are standing on a bathroom scale when you are flying in a jet airplane. for a moment the scale reads less than your
IRINA_888 [86]

Answer:

Inertia

Explanation:

When the planes moves downward a speed, the weight of the person will decrease a bit due to the amount of g decreases for that particular instant. The person is now experiencing a less than actual weight called as apparent weight due to the upward superposition of inertia on the body as we can see in w = m g .

7 0
3 years ago
Suppose a child drives a bumper car head on into the side rail which exerts a force of 4000 N on the car for 0.200 s. What impul
Ghella [55]

Por the impulse, use the formula:

I = F * t

Now, we know:

4000 N = 4000 kg*m/s²

Replacing we have:

I = 4000 kg*m/s² * 0,200 s

Resolving:

I = 800 kg.m/s²

The impulse is <u>800 kg.m/s²</u>

7 0
3 years ago
Which of the following is the correct definition of conduction? A. the transfer of heat by currents within a liquid or gas B. th
dolphi86 [110]
I believe it's B. the transmission of heat across matter
6 0
3 years ago
Read 2 more answers
Consider an electron with charge −e and mass m orbiting in a circle around a hydrogen nucleus (a single proton) with charge +e.
alexandr1967 [171]

Answer:

v=\sqrt{k\frac{e^2}{m_e r}}, 2.18\cdot 10^6 m/s

Explanation:

The magnitude of the electromagnetic force between the electron and the proton in the nucleus is equal to the centripetal force:

k\frac{(e)(e)}{r^2}=m_e \frac{v^2}{r}

where

k is the Coulomb constant

e is the magnitude of the charge of the electron

e is the magnitude of the charge of the proton in the nucleus

r is the distance between the electron and the nucleus

v is the speed of the electron

m_e is the mass of the electron

Solving for v, we find

v=\sqrt{k\frac{e^2}{m_e r}}

Inside an atom of hydrogen, the distance between the electron and the nucleus is approximately

r=5.3\cdot 10^{-11}m

while the electron mass is

m_e = 9.11\cdot 10^{-31}kg

and the charge is

e=1.6\cdot 10^{-19} C

Substituting into the formula, we find

v=\sqrt{(9\cdot 10^9 m/s) \frac{(1.6\cdot 10^{-19} C)^2}{(9.11\cdot 10^{-31} kg)(5.3\cdot 10^{-11} m)}}=2.18\cdot 10^6 m/s

7 0
4 years ago
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