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Shalnov [3]
3 years ago
14

Why do scientists ask questions?

Physics
2 answers:
aleksandrvk [35]3 years ago
8 0
To clear their doubts and make/discover new things

andrezito [222]3 years ago
4 0
Scientists ask questions so that they can be answered. As well as solving the world and its mysteries
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The upper part of the mantle and the crust are called the__________
swat32

Answer: Lithosphere

Explanation:

7 0
3 years ago
Read 2 more answers
An unwary football player collides with a padded goalpost while running at a velocity of 9.50 m/s and comes to a full stop after
Amanda [17]

Answer:

(a) The collision lasts for 0.053 s.

(b) The deceleration is 180.5 m/s².

Explanation:

Given:

Initial velocity of the player (u) = 9.50 m/s

Final velocity of the player (v) = 0 m/s (Comes to a stop)

Displacement of the player (S) = 0.250 m

We know that, using equation of motion relating displacement (S), acceleration (a), initial velocity (u) and final velocity (v), we have:

v^2=u^2+2aS

Expressing in terms of 'a', we get:

a=\frac{v^2-u^2}{2S}

Plug in the given values and solve for 'a'. This gives,

a=\frac{0-9.50^2}{2\times 0.250}\\\\a=\frac{-90.25}{0.5}=-180.5\ m/s^2

Therefore, the acceleration of the player is -180.5 m/s². So, the deceleration is 180.5 m/s².

Now, using the first equation of motion, we have:

v=u+at\\\\t=\frac{v-u}{a}

Plug in the given values and solve for 't'. This gives,

t=\frac{0-9.5}{-180.5}\\\\t=0.053\ s

Therefore, the the collision will last for 0.053 s.

(a) The collision lasts for 0.053 s.

(b) The deceleration is 180.5 m/s².

8 0
3 years ago
A police car is at rest parallel to the highway and measures the speed of cars. It sends the signal with a frequency of 1200 Hz,
masha68 [24]

Answer:

a) The car was moving at a speed of 29.167\ m.s^{-1}

b) The negative sign of v_o denotes that the observer is coming towards the police car which is the source of the sound.

c) f_o=1283.33\ Hz

Explanation:

Given:

  • original frequency of the source, f=1200\ Hz
  • speed of the source, v_s=0\ m.s^{-1}
  • velocity of the obstacle car be, v_o
  • speed of sound, s=350\ m.s^{-1}
  • observed frequency, f_o=1100\ Hz

<u>Using the equation from the Doppler's effect:</u>

\frac{f_o}{f} =\frac{(s+v_o)}{(s-v_s)}

\frac{1100}{1200} =\frac{(350+v_o)}{350-0}

v_o=-29.167\ m.s^{-1}

a)

The car was moving at a speed of 29.167\ m.s^{-1}

b)

The negative sign of v_o denotes that the observer is coming towards the police car which is the source of the sound.

c)

Now when, v_s=50\ m.s^{-1}

Then, f_o=?

Using the Doppler's eq.:

\frac{f_o}{1200} =\frac{(350+(-29.167))}{(350-50)}

f_o=1283.33\ Hz

3 0
3 years ago
19. A 0.0340 kg bullet traveling at 120 m/s embeds itself in a 1.24 kg wooden block which
Blababa [14]

Answer: x ≈ 36.3 cm

Explanation:

Conservation of momentum during the collision

0.0340(120) + 1.24(0) = (0.0340 + 1.24) v

v = 3.2025 m/s

The kinetic energy of the block/bullet mass will convert to spring potential

½kx² = ½mv²

x = √(mv²/k)

x = √(1.274(3.2025²) / 99.0)

x = 0.363293... ≈ 36.3 cm

3 0
3 years ago
A 1,120 kg car is travelling with a speed of 40 m/s. Find its energy.
serious [3.7K]

Answer:

this vehichle has 896,000 jules of energy

Explanation: KE=1/2mv squared, KE is Kinetic energy. m is mass and v is velocity

8 0
2 years ago
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