Answer:
0.4 ohms.
Explanation:
From the circuit,
The voltage reading in the voltmeter = voltage drop across each of the parallel resistance.
1/R' = 1/R1+1/R2
R' = (R1×R2)/(R1+R2)
R' = (2.4×1.2)/(2.4+1.2)
R' = 2.88/3.6
R' = 0.8 ohms.
Hence the current flowing through the circuit is
I = V'/R'................ Equation 1
Where V' = voltmeter reading
I = 6/0.8
I = 7.5 A
This is the same current that flows through the variable resistor.
Voltage drop across the variable resistor = 9-6 = 3 V
Therefore, the resistance of the variable resistor = 3/7.5
Resistance = 0.4 ohms.
Answer:
Golf ball A was hit with a weaker force
Explanation:
Golf ball B went a larger distance than golf ball A, so we could think friction affected golf ball A rather than golf ball B. That is why the first two choices are wrong.
The strongest forced applied made golf ball B go further.
The terminating pin strikes the preliminary, making it detonate. The flash from the groundwork touches off the black powder. Gas changed over from the consuming powder quickly extends in the cartridge. ... The shot's speed and getting away from gases produce a "blast."
The answer is 34 you have to add the numbers and divide them by how many numbers there are
Answer:
Ffriction = 217.7[N]
Explanation:
First, we must find the mass of the box, we must remember that the weight is defined as the product of the mass by acceleration.

where:
w = weight [N] (units of Newtons)
m = mass [kg]
g = gravity acceleration = 9.81 [m/s²]
![1300=m*9.81\\m=132.51[kg]](https://tex.z-dn.net/?f=1300%3Dm%2A9.81%5C%5Cm%3D132.51%5Bkg%5D)
Now we must use Newton's second law, which tells us that the sum of forces is equal to the product of mass by acceleration.
∑F = m*a
where:
∑F sum of forces
m = mass = 132.51[kg]
a = acceleration = 1.3[m/s²]
We must know that the forces that act are the horizontal force that moves the box and the friction force in the negative direction that acts against the movement.
Now replacing:
![390-f_{friction}=132.51*1.3\\390-172.26=f_{friction}\\f_{friction}=217.7[N]](https://tex.z-dn.net/?f=390-f_%7Bfriction%7D%3D132.51%2A1.3%5C%5C390-172.26%3Df_%7Bfriction%7D%5C%5Cf_%7Bfriction%7D%3D217.7%5BN%5D)