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Harrizon [31]
3 years ago
5

An alpha particle (which has two protons) is sent directly toward a target nucleus with 90 protons. the alpha particle has a kin

etic energy of 0.45 pj when far away. what is the least center-to-center distance that the alpha particle will be from the target nucleus, assuming that the nucleus does not move?
Physics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0
It does not move because of the sun the sun has no energy.
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A manometer is used to measure the air pressure in a tank. The fluid used has a specific gravity of 1.25, and the differential h
Sloan [31]

Answer:

77.88 lbm/ft³

Explanation:

Given,

Specific gravity, SG = 1.25

Density of water, ρ = 62.30 lbm/ft³

density of the fluid =

   = S.G x ρ_{water}

   = 62.30 x 1.25

   = 77.88 lbm/ft³

Density of the fluid is equal to 77.88 lbm/ft³

3 0
3 years ago
The equation for the speed of a satellite in a circular orbit around the earth depends on mass. Which mass?
katovenus [111]
<h3><u>Question: </u></h3>

The equation for the speed of a satellite in a circular orbit around the Earth depends on mass. Which mass?

a. The mass of the sun

b. The mass of the satellite

c. The mass of the Earth

<h3><u>Answer:</u></h3>

The equation for the speed of a satellite orbiting in a circular path around the earth depends upon the mass of Earth.

Option c

<h3><u> Explanation: </u></h3>

Any particular body performing circular motion has a centripetal force in picture. In this case of a satellite revolving in a circular orbit around the earth, the necessary centripetal force is provided by the gravitational force between the satellite and earth. Hence F_{G} = F_{C}.

Gravitational force between Earth and Satellite: F_{G} = \frac{G \times M_e \times M_s}{R^2}

Centripetal force of Satellite :F_C = \frac{M_s \times V^2}{R}

Where G = Gravitational Constant

M_e= Mass of Earth

M_s= Mass of satellite

R= Radius of satellite’s circular orbit

V = Speed of satellite

Equating  F_G = F_C, we get  

Speed of Satellite V =\frac{\sqrt{G \times M_e}}{R}

Thus the speed of satellite depends only on the mass of Earth.

6 0
4 years ago
Nathan drops marbles down two ramps that have different lengths. It takes the marbles 10 seconds to reach the bottom of both ram
Sonbull [250]
<h2><u>Full Question:</u></h2>

Nathan drops marbles down two ramps that have different lengths. It takes the marbles 10 seconds to reach the bottom of both ramps.Which statement is TRUE?

answer choices

Marble 1 has a faster speed than Marble 2.

Marble 2 has a faster speed than Marble 1.

Both the marbles travel at the same speed.

There is not enough data to compare the speeds of marbles.

<h2><u>Answer:</u></h2>

Marble 2 has a faster speed than Marble 1.

Option B.

<h3><u>Explanation:</u></h3>

The speed is defined as the distance covered per unit time. Here in the question, 2 balls cover equal distances in same time.

Time taken by the ball = 10 seconds.

Distance covered by 1st ball = 20 cm.

Distance covered by 2nd ball = 3cm.

So speed of the 1st ball = 2cm/sec.

Speed of the 2nd ball = 3 cm /sec.

So,it's very much evident that speed of 2nd Marble is much higher than the speed of the 1st marble.

5 0
3 years ago
imagine riding a single-speed bicycle. why do you have to push harders on the pedals to start the bicycle moving than to keep it
Flura [38]
A large force is required to accelerate the mass of the bicycle and rider. Once the desired constant velocity is reached, a much smaller force is sufficient to overcome the ever-present frictional forces. 
3 0
3 years ago
A 0.14-MIN baseball is dropped from rest. It has a momentum of 0.90 kg⋅m/skg⋅m/s just before it lands on the ground.
nikitadnepr [17]

The time spent in the air by the ball at the given momentum is 6.43 s.

The given parameters;

  • <em>momentum of the ball, P = 0.9 kgm/s</em>
  • <em>weight of the ball, W = 0.14 N</em>

The impulse experienced by the ball is calculated as follows;

Ft = \Delta P

where;

Ft is impulse

\Delta P is change in momentum

The time of motion of the ball is calculated as follows;

t = \frac{\Delta P}{F} \\\\t = \frac{0.9 - 0}{0.14} \\\\t = 6.43 \ s

Thus, the time spent in the air by the ball at the given momentum is 6.43 s.

Learn more here:brainly.com/question/13468390

7 0
2 years ago
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