All categories

2 years ago

Composite Figures Question 2. A. 74 ft B. 24 ft C. 81 ft D. 69 ft

Mathematics

2 answers:

Alexxx [7]2 years ago

4 0

D. 69
Break up the figure then multiply the numbers.
9 x 5=45.
4 x 6=24.
Then add.
45+24=69

Elena L [17]2 years ago

4 0

The Correct answer is D

You might be interested in

Inequality help!<br><br>so I'm thinking it's choice one...would that be right?

professor190 [17]

The answer is choice 1

6 0

3 years ago

Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

3 years ago

If the volume of the solid shown in the figure is 438 cubic inches, find the value of x.

svetoff [14.1K]

Answer:

what

Step-by-step explanation:

what figure

7 0

1 year ago

Patricia can buy individual songs for $1.00 to download. Also, an entire album costs $10.00 to download. She can spend no more t

Burka [1]

The system of linear inequalities x + 10y ≤ 80, x ≥ 30 and y ≤ 4 is represented in a graph below

<h3>Graph of Linear Inequality</h3>

The graph of an inequality in two variables is the set of points that represents all solutions to the inequality. A linear inequality divides the coordinate plane into two halves by a boundary line where one half represents the solutions of the inequality.

To solve this problem, we would require the use of graph which can easily be done with a graphing calculator.

x + 10y ≤ 80

x ≥ 30

y ≤ 4

The graph of the inequalities is attached below

Learn more on graph of linear inequality here;

brainly.com/question/19443475

#SPJ1