Well,. you could say bees in hive + bees in garden = bees in total.
Answer:
The actual mass of the book is between 481 . 5 g and 418 . 5 g.
Step-by-step explanation:
The mass of the book on the scale = 450 g
The percentage error in the scale = 7%
So, the actual mass of the book is 450 g ± 7%
Now, 7 % of the mass 450 g = 
⇒ 7% of 450 g = 31.5 g
Now, the Actual mass of the book = 450 g ± 31.5 g
450 g + 31.5 g = 481 . 5 g
450 g - 31.5 g = 418 . 5 g
Hence the actual mass of the book is between 481 . 5 g and 418 . 5 g.
Two pair of numbers are said to be relatively prime if there is no integer greater than 1, that divides them both.
Consider the given pair of the numbers to identify which pair is relatively prime.
1. Consider 42 and 77
7 is the number which divides 42 and 77 both. Therefore, they are not relatively prime.
2. Consider 34 and 55
Since, there is no number greater than 1, which divides both the numbers. So, they are relatively prime numbers.
3. Consider 45 and 102
3 is the number divides 45 and 102 both. Therefore, they are not relatively prime.
4. Consider 99 and 123
3 is the number divides 99 and 123 both. Therefore, they are not relatively prime.
Therefore, Option B is the correct answer.
12 red counters
7 more red counters than yellow counters
12 - 7 = 5 yellow counters
Dara has 5 yellow counters.
Answer:
m<GFA = 110
Step-by-step explanation:
1. ABCD - parallelogram Definition of a parallelogram
(AB ll CD) (AD ll BC)
2. m<B + m<C = 180 Consectuive angles in a
110 + m<C = 180 parallelogram are supplementary
m<C = 70
3. m<GCB = 1/2 m<C Definition of angles bisector
m<GCB = 70
4. m<B = m<D = 110 Opposite angles in a
parrallelogram are congruent
5. m<CDG = 1/2 m<D Defintion of an angle bisector
m<CDG = 55
6. m<GCB+m<CDG+m<CGD=180 Sum of anlges in a triangle (ΔCDG)
70 + 55 + m<CGD = 180
125 + m<CGD = 180
m<CGD = 55
7. m<CGD + m<DGF = 180 Linear pair, supplmentary angles
55 + m<DGF = 180
m<DGF = 125
8. m<C = m<A = 70 Opposite angles in a paralellogram
are congruent
9. m<ADG = 1/2m<D Definiton of an angle bisector
m<ADG = 55
10.m<ADG+m<DFG+m<GFA+m<A=360 Sum of angles in quadrilateral
55 + 125 + m<GFA + 70 = 360 DGFA
m<GFA + 250 = 360
m<GFA = 110
