A) divide by 100. A meter is 100 centimeters so that’s how you can tell
Answer:
6.4×10¯³ g of O₂.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CH₄ + 2O₂ —> CO₂ + 2H₂O
Next, we shall determine the masses of CH₄ and O₂ that reacted from the balanced equation. This can be obtained as follow:
Molar mass of CH₄ = 12 + (4×1)
= 12 + 4
= 16 g/mol
Mass of CH₄ from the balanced equation = 1 × 16 = 16 g
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ from the balanced equation = 2 × 32 = 64 g
SUMMARY:
From the balanced equation above,
16 g of CH₄ reacted with 64 g of O₂.
Finally, we shall determine the mass of O₂ needed to react with 1.6×10¯³ g of CH₄. This can be obtained as illustrated below:
From the balanced equation above,
16 g of CH₄ reacted with 64 g of O₂.
Therefore, 1.6×10¯³ g of CH₄ will react with = (1.6×10¯³ × 64) / 16 = 6.4×10¯³ g of O₂
Thus, 6.4×10¯³ g of O₂ is needed for the reaction.
To determine this, lets use the atomic mass for each element to determine the corresponding number of moles for a given mass of 1 g.
Mo: 95.94 g/mol
1 g/95.94 g/mol = 0.01042 moles Mo
Se: 78.96 g/mol
1 g/78.96 g/mol = 0.01266 moles Se
Na: 22.99 g/mol
1 g/22.99 g/mol = 0.0435 moles Na
Br: 79.9 g/mol
1 g/79.9 g/mol = 0.0125 moles Br
<em>Thus, the answer is Na.</em>
Answer:
there are elemental molecules, made from one type of atom (pure), example: oxygen and there are compound molecules, made from more then one type of atom, for example carbon dioxide
