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JulsSmile [24]
4 years ago
8

Write and balance molecular equations for the following reactions between aqueous solutions. You will need to decide on the form

ulas and phases of the products in each of the cases. An aqueous solution of lead(II) nitrate is mixed with an aqueous solution of sodium iodide
Chemistry
1 answer:
musickatia [10]4 years ago
4 0

Answer:

This is the balanced equation:

Pb(NO₃)₂ (aq) + 2NaI (aq) → 2NaNO₃ (aq)  +  PbI₂ (s) ↓    

Explanation:

This are the reactants:

PbNO₃

NaI

Iodide can react to Pb²⁺ to make a solid compound.

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If 4.35 grams of zinc metal react with 35.8 grams of silver nitrate, how many grams of silver metal can be formed and how many g
vaieri [72.5K]
The balanced chemical reaction is written as:

<span>Zn + 2AgNO3 = Zn(NO3)2 + 2Ag

To determine the grams of silver metal that is being produced, it is important to first determine which is the limiting reactant and the excess reactant from the given initial amounts. We do as follows:

4.35 g Zn ( 1 mol / 65.38 g ) ( 2 mol AgNO3 / 1 mol Zn ) = 0.1331 mol AgNO3 needed
35.8 g AgNO3 ( 1 mol / 169.87 g ) ( 1 mol Zn / 2 mol AgNO3 ) = 0.1054 mol Zn needed

Therefore, the limiting reactant would be the zinc metal since it would be consumed completely in the reaction. The excess amount of AgNO3 would be:

0.2107 mol AgNO3 - 0.1331 mol AgNO3 = 0.0776 mol AgNO3 left ( 169.87 g / 1 mol ) = 13.19 g AgNO3 left

0.0665 mol Zn ( 2 mol Ag / 1 mol Zn) ( 107.9 g / 1 mol) = 14.3581 g Ag produced</span>
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How many grams are in 7.32 x 1023 molecules of potassium carbonate (K2CO3)?
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